[SOLVED] If a var is in an array echo this

[xXREDXIIIXx]

OK I want to mark a checkbox as checked if the gameid is in the array how can i manage this?

 

<form name="previous_games" method="post" action="edit_games.php">  
   
Select previously played games
<br /><br />  
   
<?php  
$query = mysql_query("SELECT gameid, title FROM games");
$i = 1;

$numbers = mysql_fetch_array(mysql_query("SELECT pgames FROM gamers WHERE gamerid='1'"));
$nums = $numbers['pgames'];
// This is 1, 2, 3, 4, 5, 6, 7

$checkNums = explode(", ", $nums);
echo "checkNums: ".$checkNums;

while ($row = mysql_fetch_array($query))  
{ ?>
<input type='checkbox' name="pgames[]" value="<?php echo $row['gameid']; ?>" <?php if($checkNums == $row['gameid']){ echo 'seleceted="selected"';} ?> /> <?php echo $row['title']; ?> <br />
<?php } ?>  
<br /><br />  
<input type="submit" value="Add Games">  
</form>  

[p2grace]

in_array()

 

http://us3.php.net/manual/en/function.in-array.php

[smerny]

<input type='checkbox' name="pgames[]" value="<?php echo $row['gameid']; ?>" <?php if($checkNums == $row['gameid']){ echo " checked";} ?> /> <?php echo $row['title']; ?> <br />

<?php } ?> 

[smerny]

although I would personally do the whole thing in one echo like this

 

echo "<input type='checkbox' name='pgames[]' value='".$row['gameid']."' ".($checkNums
== $row['gameid'] ? "checked")." />".$row['title']; 

[xXREDXIIIXx]

although I would personally do the whole thing in one echo like this

 

echo "<input type='checkbox' name='pgames[]' value='".$row['gameid']."' ".($checkNums
== $row['gameid'] ? "checked")." />".$row['title']; 

 

Using this i get a unexpected ) so i changed to this:

 

echo "<input type='checkbox' name='pgames[]' value='".$row['gameid']."' "; if(in_array($row['gameid'], $checkNums)){echo "checked";} echo " />".$row['title']."<br />";

 

It ONLY works if i define the array manually :S

$checkNums = array(1, 2, 3, 4, 5, 6, 7); // THIS WORKS
$checkNums = array($nums); // THIS DONT

 

<?php  
$query = mysql_query("SELECT gameid, title FROM games");

$numbers = mysql_fetch_array(mysql_query("SELECT pgames FROM gamers WHERE gamerid='1'"));
$nums = $numbers['pgames'];

echo "Nums: ".$nums."<br />";
//$checkNums = array(1, 2, 3, 4, 5, 6, 7); //THIS WORKS
$checkNums = array($nums); // THIS DONT

while ($row = mysql_fetch_array($query))  
{
echo "<input type='checkbox' name='pgames[]' value='".$row['gameid']."' "; if(in_array($row['gameid'], $checkNums)){echo "checked";} echo " />".$row['title']."<br />";
} ?>  

[smerny]

echo "Nums: ".$nums."<br />";

 

 

what does that output?

[xXREDXIIIXx]

echo "Nums: ".$nums."<br />";

 

 

what does that output?

 

Nums: 1, 2, 3, 4, 5, 6, 7

[smerny]

well that's not an array, it's just a string of numbers

 

do this

$checkNums1 = array(1, 2, 3, 4, 5, 6, 7); //THIS WORKS
$checkNums2 = array($nums); // THIS DONT

echo "array(1,2...) = ".$checkNums1."<br>";
echo "array(nums) = ".$checkNums2.";

 

and you'll see the difference between the two....

 

and i actually see that i didn't fully read your post to begin with... didn't realize you were looking for an array of numbers at first

[xXREDXIIIXx]

well that's not an array, it's just a string of numbers

 

do this

$checkNums1 = array(1, 2, 3, 4, 5, 6, 7); //THIS WORKS
$checkNums2 = array($nums); // THIS DONT

echo "array(1,2...) = ".$checkNums1."<br>";
echo "array(nums) = ".$checkNums2.";

 

and you'll see the difference between the two

 

how am I going to see a difference if they will output 'Array'?

[xXREDXIIIXx]

So i cant use the var $nums in the array???

[xXREDXIIIXx]

SOLVED after I was using print_r i saw explode was coming up as an array so i used that

 

<?php  
$query = mysql_query("SELECT gameid, title FROM games");

$numbers = mysql_fetch_array(mysql_query("SELECT pgames FROM gamers WHERE gamerid='1'"));
$nums = $numbers['pgames'];

$checkNums = explode(", ",$nums);

while ($row = mysql_fetch_array($query))  
{
echo "<input type='checkbox' name='pgames[]' value='".$row['gameid']."' "; if(in_array($row['gameid'], $checkNums)){echo "checked";} echo " />".$row['title']."<br />";
} ?>  

 

Thanks Guys good night