upload scrip blank

[chanfuterboy]

Hi,

 

I was working on a uplaod script, after i upload a picture in a form in a separate page, the upload script keep in blank why? should i mist something?

 

<?php

 

// if something was posted, start the process...

if(isset($_POST['upload']))

{

// define the posted file into variables

$name = $_FILES['picture']['name'];

$tmp_name = $_FILES['picture']['tmp_name'];

$type = $_FILES['picture']['type'];

$size = $_FILES['picture']['size'];

 

// get the width & height of the file (we don't need the other stuff)

list($width, $height, $typeb, $attr) = getimagesize($tmp_name);

   

// if width is over 600 px or height is over 500 px, kill it   

if($width>600 || $height>500)

{

echo $name . "'s dimensions exceed the 600x500 pixel limit.";

echo ?> <a href="form.html">Click here</a> to try again. <? ;

die();

}

// if the mime type is anything other than what we specify below, kill it   

if(!(

$type=='images/jpeg' ||

$type=='images/png' ||

$type=='images/gif'

)) {

echo $type .  " is not an acceptable format.";

echo ?> <a href="form.html">Click here</a> to try again. <? ;

die();

}

 

// if the file size is larger than 350 KB, kill it

if($size>'350000') {

echo $name . " is over 350KB. Please make it smaller.";

echo ?> <a href="form.html">Click here</a> to try again. <? ;

die();

}

// if your server has magic quotes turned off, add slashes manually

if(!get_magic_quotes_gpc()){

$name = addslashes($name);

}

 

// open up the file and extract the data/content from it

$extract = fopen($tmp_name, 'r');

$content = fread($extract, $size);

$content = addslashes($content);

fclose($extract); 

// connect to the database

include "connect.php";

 

// the query that will add this to the database

$addfile = "INSERT INTO files (name, size, type, content ) ".

          "VALUES ('$name', '$size', '$type', '$content')";

 

mysql_query($addfile) or die(mysql_error());

 

// get the last inserted ID if we're going to display this image next

$inserted_fid = mysql_insert_id();

 

mysql_close(); 

 

// display the image

?>

<div align="center">

    <strong><? echo $name; ?><br>

    </strong><img name="<? echo $name; ?>" src="getpicture.php?fid=<? echo $inserted_fid; ?>" alt="Unable to view image #<? echo $inserted_fid; ?>">

    <br>

    <a href="form.html">upload more images</a>

</div>

<?

// we still have to close the original IF statement. If there was nothing posted, kill the page.

}else{die("No uploaded file present");

}

?> 

[alexdemers]

Like some people have here in their signature:

 

<?php
ini_set('display_errors', 1);
error_reporting(E_ALL | E_STRICT);
?>

 

Put that at the top of your file. You will know any errors.

[chanfuterboy]

hi,

 

i try it that, but the page is not getting up

[br3nn4n]

Just thinking the exact same thing. Or check your PHP error log, it should tell you. If there's no errors, try to do a var_dump($_POST['upload']) and see what you get (if anything).

 

Put this in the top of the script that processes the upload:

 

error_reporting(E_ALL);

 

And report back

[chanfuterboy]

hi,

 

still nothing

[alexdemers]

It could be one of your die(). Follow the logic and try var_dump()ing different variables to see where your logic goes.

[ldougherty]

So how exactly is your script supposed to work, you state something about "uploading a picture in a form in a separate page".

 

Does the upload itself actually work or no? If you can give us the URL where you are running this script it might be helpful so we can see the code in action.

[br3nn4n]

So how exactly is your script supposed to work, you state something about "uploading a picture in a form in a separate page".

 

Does the upload itself actually work or no? If you can give us the URL where you are running this script it might be helpful so we can see the code in action.

 

Pretty sure we're not allowed to self-promote around here, even if it's in order to help solve coding problems...not sure if I'm wrong about that rule..

[chanfuterboy]

Yes i got the error it was those lines echo ?> <a href="form.html">Click here</a> to try again. <?

[chanfuterboy]

now i have another problem, when i upload a name let say winter.php  in upload script it change the name in another name, put that the upload does not read it. what can be the problem?

[br3nn4n]

Can you rephrase that?

[chanfuterboy]

ok, i have form.html there I upload a picture winter.jpg.  as it check the upload.php script, it result the image, with another name + extention. why is that happening?