pluto Posted August 7, 2009 Share Posted August 7, 2009 Hi guys, Me once again, I'm working with a PHP page, which the output I'd like to be formatted by a css file. This is the code I have so far. <?php session_start(); require("con_mgr.php"); $chapSelect = $_POST['chapSelect']; $_SESSION['wordArray']=$get_field; $_SESSION['currentWord']=$value; $result = mysql_query("SELECT GreekWord FROM WORD where Chapter >= $chapSelect"); $num_rows = mysql_num_rows($result); $get_field = mysql_fetch_row($result); foreach($get_field as $value) { $display="<HTML>"; $display.="<link rel=\"stylesheet\" type=\"text/css\" href=\"test.css\">"; $display.="<div id=\"testWord\">"; $display.="<?php echo $value; ?>"; $display.="</div>"; $display.="</HTML>"; } echo($display); //header("Location:http://localhost/SessionDemo/demo2.php"); ?> I have a css file called test.css which has a div section that formats the text as red, and makes the font quite big. At least that's the plan. I've tried everything I can think of, but it won't return anything at all. And I'm not sure why it's not doing that. Or ideally I'd like the variable to be passed to a HTML (or the value thereof, I'm thinking like a Java coder again!!!) Any help would be awesome. Thanks Pluto Quote Link to comment Share on other sites More sharing options...
mikesta707 Posted August 7, 2009 Share Posted August 7, 2009 there is a syntax error there. You don't need to echo PHP inside php tags <?php session_start(); require("con_mgr.php"); $chapSelect = $_POST['chapSelect']; $_SESSION['wordArray']=$get_field; $_SESSION['currentWord']=$value; $result = mysql_query("SELECT GreekWord FROM WORD where Chapter >= $chapSelect"); $num_rows = mysql_num_rows($result); $get_field = mysql_fetch_row($result); foreach($get_field as $value) { $display="<HTML>"; $display.="<link rel=\"stylesheet\" type=\"text/css\" href=\"test.css\">"; $display.="<div id=\"testWord\">"; $display.="$value"; $display.="</div>"; $display.="</HTML>"; } echo($display); //header("Location:http://localhost/SessionDemo/demo2.php"); ?> Quote Link to comment Share on other sites More sharing options...
pluto Posted August 7, 2009 Author Share Posted August 7, 2009 You are a total legend!! Thank you so very much Quote Link to comment Share on other sites More sharing options...
wildteen88 Posted August 7, 2009 Share Posted August 7, 2009 pluto You should note that the following highlighted lines foreach($get_field as $value) { $display="<HTML>"; $display.="<link rel=\"stylesheet\" type=\"text/css\" href=\"test.css\">"; $display.="<div id=\"testWord\">"; $display.="$value"; $display.="</div>"; $display.="</HTML>"; } Should be outside of your loop. Otherwise they will be defined more than once, which will cause invalid HTML. Quote Link to comment Share on other sites More sharing options...
watsmyname Posted August 7, 2009 Share Posted August 7, 2009 nothing seems wrong in a code except that $display.="<?php echo $value; ?>", you dont need php tag inside php tag and rest look below <?php foreach($get_field as $value) { $display="<HTML>"; $display.="<link rel=\"stylesheet\" type=\"text/css\" href=\"test.css\">"; $display.="<div id=\"testWord\">"; $display.="<?php echo $value; ?>"; $display.="</div>"; $display.="</HTML>"; } ?> Why on earth you are putting <html> inside loop? you should put it outside...do like this <?php echo "<HTML>"; echo "<link rel='stylesheet' type='text/css' href='test.css'>"; foreach($get_field as $value) { $display.="<div id=\"testWord\">"; $display.=$value; $display.="</div>"; } echo "</HTML>"; ?> Quote Link to comment Share on other sites More sharing options...
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