[SOLVED] Database field in textbox

halfman · August 11, 2009

estimatedDelivery is a reference when it is in the name = "estimatedDelivery" in your text box,

when PHP collect all the vars they all will have the same name and they over right eachother,

and you will get the last $_POST['estimatedDelivery'] whereas if you have got name="estimatedDelivery[$id]" then every reference has its own name and you will be end up with multiple POSTs like this

$_POST[estimatedDelivery][1] = "DATE"

$_POST[estimatedDelivery][2] = "DATE"

$_POST[estimatedDelivery][3] = "DATE"

Give a shot at this code and see what will happen

<?php 

foreach ($_POST['estimatedDelivery'] as $key => $val) {
   // KEY WILL BE THE ID AND VAL IS THE VALUE OF EACH POST
   // your update script will be :: UPDATE tableName SET estimatedDelivery = '".$val."' WHERE id = '".$key."'
}
?>
<form action='process.php' method='post'>
  <?php
while($row = mysql_fetch_array($result))
  {
  $date2 = $row['estimatedDelivery'];;
  $timestamp2 = strtotime($date2);
  $new_date2 = date("d-m-Y",$timestamp2);
  echo "<td> <input type='text' name='estimatedDelivery[".$id."]' value=".$new_date2."></td>";   //use array if you want to send multiple values for one variable name then use foreach or while to extract the variable name and values   
  }
  echo "<input type='submit' name='submit' value='Submit updated delivery dates'></form>";
  ?>

jeeves245 · August 11, 2009

Thanks again for the info.

I gave that code a go but when I click submit i'm just getting a blank page with "Error: Query was empty".

Chances are i've done something wrong.. i'll keep at it

halfman · August 11, 2009

Thanks again for the info.

I gave that code a go but when I click submit i'm just getting a blank page with "Error: Query was empty".

Chances are i've done something wrong.. i'll keep at it

check your query again, check if you extracted values and keys correctly,

// HOW TO EXTRACT THE VALUE -- very simplified mate not a very clever approach

foreach ($_POST as $key => $val) {

foreach ($val as $k => $v) {

echo $v; // PUT THE SQL CODE IN HERE AND $key WILL BE YOUR TRANSFFERED id

// UPDATE tableName SET 'filedName' = '".$v."' WHERE id = '".$key."'

}

jeeves245 · August 11, 2009

Ok. I tried this to see what was being echoed:

foreach ($_POST['estimatedDelivery'] as $key => $val) {
         echo "<br>";
	 echo $val;
	 echo "<br>";
	 echo $key;

   }

And I get this result which is correct:

16-07-2009

0

17-07-2009

1

18-07-2009

2

19-07-2009

3

20-07-2009

4

21-07-2009

5

22-07-2009

6

23-07-2009

7

But when I insert the SQL statement in the for loop I still get "Error: Query was empty"..

I'm using this query:

foreach ($_POST['estimatedDelivery'] as $key => $val) {
          mysql_query("UPDATE smail SET estimatedDelivery = '".$val."' WHERE id = '".$key."'");
   }
}

I also tried your modified for loop that you posted above but I got the same result.

halfman · August 11, 2009

Ok. I tried this to see what was being echoed:
foreach ($_POST['estimatedDelivery'] as $key => $val) {
         echo "<br>";
	 echo $val;
	 echo "<br>";
	 echo $key;

   }
And I get this result which is correct:

16-07-2009

0

17-07-2009

1

18-07-2009

2

19-07-2009

3

20-07-2009

4

21-07-2009

5

22-07-2009

6

23-07-2009

7

But when I insert the SQL statement in the for loop I still get "Error: Query was empty"..

I'm using this query:
foreach ($_POST['estimatedDelivery'] as $key => $val) {
          mysql_query("UPDATE smail SET estimatedDelivery = '".$val."' WHERE id = '".$key."'");
   }
}
I also tried your modified for loop that you posted above but I got the same result.

Try to echo this and let me know what is the result.

foreach ($_POST['estimatedDelivery'] as $key => $val) {
         echo "UPDATE smail SET estimatedDelivery = '".$val."' WHERE id = '".$key."'"."<br>";
      // mysql_query("UPDATE smail SET estimatedDelivery = '".$val."' WHERE id = '".$key."'");
   }
}

jeeves245 · August 11, 2009

UPDATE smail SET estimatedDelivery = '16-07-2009' WHERE id = '0'
UPDATE smail SET estimatedDelivery = '17-07-2009' WHERE id = '1'
UPDATE smail SET estimatedDelivery = '18-07-2009' WHERE id = '2'
UPDATE smail SET estimatedDelivery = '19-07-2009' WHERE id = '3'
UPDATE smail SET estimatedDelivery = '20-07-2009' WHERE id = '4'
UPDATE smail SET estimatedDelivery = '21-07-2009' WHERE id = '5'
UPDATE smail SET estimatedDelivery = '22-07-2009' WHERE id = '6'
UPDATE smail SET estimatedDelivery = '23-07-2009' WHERE id = '7'
Error: Query was empty

halfman · August 11, 2009

UPDATE smail SET estimatedDelivery = '16-07-2009' WHERE id = '0'
UPDATE smail SET estimatedDelivery = '17-07-2009' WHERE id = '1'
UPDATE smail SET estimatedDelivery = '18-07-2009' WHERE id = '2'
UPDATE smail SET estimatedDelivery = '19-07-2009' WHERE id = '3'
UPDATE smail SET estimatedDelivery = '20-07-2009' WHERE id = '4'
UPDATE smail SET estimatedDelivery = '21-07-2009' WHERE id = '5'
UPDATE smail SET estimatedDelivery = '22-07-2009' WHERE id = '6'
UPDATE smail SET estimatedDelivery = '23-07-2009' WHERE id = '7'
Error: Query was empty

What is the dataType for the estimatedDelivery field in your mysql? set it to varchar 200. also I would suggest running one of the update sql directly from your mysql and see if there is any error.

jeeves245 · August 11, 2009

I can't set it to varchar as it's a date and I'm using some format date functions to format it. But I'll try using the update query in phpmyadmin and see if I get any errors. Thanks.

jeeves245 · August 11, 2009

Wait...

mysql_query("UPDATE smail SET estimatedDelivery = '".$val."' WHERE id = '".$key."'");

id? Where did that come from? I have no id column...

If $key is just a number, how will the WHERE = clause work? Wouldn't it need to reference the date that I am updating?

halfman · August 11, 2009

Mate have you read the code??

You need to pass the id.

name='estimatedDelivery[".$id."]'

Maybe your id is $row['id'] so your $id = $row['id'];

<?php 

foreach ($_POST['estimatedDelivery'] as $key => $val) {
   // KEY WILL BE THE ID AND VAL IS THE VALUE OF EACH POST
   // your update script will be :: UPDATE tableName SET estimatedDelivery = '".$val."' WHERE id = '".$key."'
}
?>
<form action='process.php' method='post'>
  <?php
while($row = mysql_fetch_array($result))
  {
  $date2 = $row['estimatedDelivery'];;
  $timestamp2 = strtotime($date2);
  $new_date2 = date("d-m-Y",$timestamp2);
  echo "<td> <input type='text' name='estimatedDelivery[".$id."]' value=".$new_date2."></td>";   //use array if you want to send multiple values for one variable name then use foreach or while to extract the variable name and values   
  }
  echo "<input type='submit' name='submit' value='Submit updated delivery dates'></form>";
  ?>

jeeves245 · August 11, 2009

Right, gotcha. Thanks.

jeeves245 · August 11, 2009

Ok i'm getting there, got rid of all the errors, i'm just still a bit confused on the WHERE clause.

WHERE estimatedDelivery = '".$key."'";

Could you please elaborate on how this works? Thanks

halfman · August 11, 2009

Mate, I dont know the structure of your table so I assume that you need some kind of the WHERE condition.

I thought if you pass the id from each post you know exactly each post belongs to where in your database (Instead of using a hidden file to pass the id), so the $key is the actual passed id from your FORM, you can use it to point each record properly in its place.

for example:

UPDATE tableName SET estimatedDelivery = '".$val."' WHERE id = '".$id."'

PHP takes care of the array and the value as the array structures will get in place in the order of the submission.

for example :

[1] => ['10-10-09']

[id] => ['estimatedDelivery']

Have a read on the PHP Array in php.net it will help you a lot.

jeeves245 · August 11, 2009

Thanks mate.

halfman · August 11, 2009

Thanks mate.

No worries mate.

Any time, Let me know if you needed any more help.

Cheers

jeeves245 · August 11, 2009

Actually one more question about for loops...

I've changed things around a bit so the dates go into the correct DB rows.. so with the code below, how do I modify the for loop accordingly?

$id = $_POST['id'];
$date = $_POST['estimatedDelivery'];

foreach ($_POST['estimatedDelivery'] ??????) {
          $sql2 = "UPDATE smail SET estimatedDelivery = '".$date."' WHERE estimatedDelivery = '".$id."'";
	  mysql_query($sql2);
}

halfman · August 11, 2009

Actually one more question about for loops...

I've changed things around a bit so the dates go into the correct DB rows.. so with the code below, how do I modify the for loop accordingly?
$id = $_POST['id'];
$date = $_POST['estimatedDelivery'];

foreach ($_POST['estimatedDelivery'] ??????) {
          $sql2 = "UPDATE smail SET estimatedDelivery = '".$date."' WHERE estimatedDelivery = '".$id."'";
	  mysql_query($sql2);
}

Mate this code is wrong you wont be able to update a recored and have it as the where condition, it is not very clever of coding and I dont think it is logicly possible.

"UPDATE smail SET estimatedDelivery = '".$date."' WHERE estimatedDelivery = '".$id."'";

Needs to be:

"UPDATE smail SET estimatedDelivery = '".$date."' WHERE `id` = '".$id."'";

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[SOLVED] Database field in textbox

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