Jump to content

[SOLVED] PHP not outputting all database rows


jeeves245

Recommended Posts

(Sorry if this should be in the database forum)

 

I've been testing my program out over the last few hours to make sure there's no errors, and unfortunately I found a big one that I can't explain. Hoping for a bit of help.. i'll explain the best I can.

 

I have a database with the the fields psNumber (primary key) and estimatedDelivery (among others, but let's keep it simple).

 

Values are put into the DB from a CSV file, then outputted back to the browser when the user requests it. When I go to upload the file, I get the error

"Error: Duplicate entry '17273(or some other psNumber value)' for key 1"

even though there are no duplicate values in the CSV file. But even with the error, all information still uploads correctly to the database.

 

The real problem comes when outputting the values back to the browser. For some reason all rows are pulled out and put in the HTML table except 1. No idea why it's missing just 1 row.

 

Hopefully someone can shed some light on this?

 

This code opens the CSV file and puts everything into the database (obviously i'm not including ALL the code, just what should matter)

$file_handle = fopen("./uploads/" .  basename( $_FILES['uploadedfile']['name'])."", "rb");

while (!feof($file_handle) ) {
$line_of_text = fgets($file_handle);
$parts = explode(',', $line_of_text);
$sql="INSERT INTO db (deliveryDate, psNumber, numItems,
volume, estimatedDelivery, customerName, address1, address2, address3)
VALUES
('$parts[0]','$parts[3]','$parts[4]','$parts[8]','$parts[1]','$parts[2]','$parts[5]','$parts[6]','$parts[7]')";
mysql_query($sql);

 

And this is the code that brings it out:

while($row = mysql_fetch_array($result))
  {
  echo "<td>" . $row['estimatedDelivery'] . "</td>";
  echo "<td>" . $row['psNumber'] . "</td>";
  echo "<td>" . $row['customerName'] . "</td>";
  echo "<td>" . $row['numItems'] . "</td>";
  echo "<td>" . $row['volume'] . "</td>";
  echo "<td>" . $row['address1'] . "</td>";
  echo "<td>" . $row['address2'] . "</td>";
  echo "<td>" . $row['address3'] . "</td>";
  }

 

And here is a sample line of the CSV file:

1/07/2009,16/07/2009,customername,170395,4,2,address1,address2,address3,0.46

 

So the basic problem is everything is output except for ONE random row...

 

Any info appreciated. Thanks in advance.

 

 

Link to comment
Share on other sites

add an AUTO_INCREMENT to your primary key

 

Hm... The primary key is psNumber which already contains a unique value.

 

Plus if I change it i'm going to have to rewrite code to suit.

 

$sql="INSERT INTO db (deliveryDate, psNumber, numItems,
volume, estimatedDelivery, customerName, address1, address2, address3)
VALUES
('$parts[0]','$parts[3]','$parts[4]','$parts[8]','$parts[1]','$parts[2]','$parts[5]','$parts[6]','$parts[7]') ON DUPLICATE KEY psNumber = psNumber + 1";

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.