Jump to content

[SOLVED] preg_match accepts + although It shouldn't


DEVILofDARKNESS

Recommended Posts

That's weird because only if functions.php gives a value AA to $error the user will be added:

<?php
function nation_check($nationname,$username){
$error = "AA"; // All Allowed
if (preg_match("/^[A-Z][a-zA-Z]*$/", $nationname, $matches)) {
	$query = "SELECT nation_id FROM nations WHERE nation_name = '$nationname'";
	$result = mysql_query($query);
	if(mysql_num_rows($result) == 1){
		$error = "NNA"; // Nation Not Avaible
	}
}else{
	$error = "NNNA"; // Nation Name Not Allowed
}
if (preg_match("/^[A-Za-z][a-zA-Z0-9_]*$/", $nationname, $matches)) {
	$query = "SELECT user_id FROM users WHERE user_name = '$username'";
	$result = mysql_query($query);
	if(mysql_num_rows($result) == 1){
		$error = "UNA"; // User Not Avaible
	}
}else{
	$error = "UNNA"; // User Name Not Allowed
}
return $error;
}
?>

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.