jigsawsoul Posted August 15, 2009 Share Posted August 15, 2009 $result = "SELECT * FROM wbl_craftsperson ORDER BY name ASC"; $result = mysql_query( $result ) or die( mysql_error() ); $craftsperson1 .= '<select name="craftsperson1" id="craftsperson1">'; while( $row = mysql_fetch_assoc( $result ) ) $craftsperson1 .= '<option value="'.$row['$craftsperson_id'].'">'.$row['name'].'</option>'; $craftsperson1 .= '</select>'; Then in the html <div id="form_accountinfo" class="mb"> <h1>Send Response</h1> <p class="grey">You are currently logged in as <em><?=$username?></em>.</p> <form action="respond2.php?id=<?=$commissionid?>" method="post"> <fieldset> <label for="subject"><b>Description</b></label> <?=$current_description?> <br /> <label for="subject"><b>Comments</b></label> <?=$current_comments?> <br /> <label for="craftsperson1"><b>Crafts Person 1</b></label> <?=$craftsperson1?> <label for="quote1"><b>Quote 1</b></label> <input id="quote1" name="quote1" size="30" type="text" value="£" /><br /> <label for="craftsperson2"><b>Crafts Person 2</b></label> <?=$craftsperson2?> <label for="quote2"><b>Quote 2</b></label> <input id="quote2" name="quote2" size="30" type="text" value="£" /><br /> <input type="submit" value="Send Response" class="primary" /> </fieldset> </form> Page 2 $craftsperson1 = $_POST['craftsperson1']; echo $craftsperson1; exit; But i get nothing i have checked all the names on my pages and database but everything to be seems fine.. ? Link to comment https://forums.phpfreaks.com/topic/170422-solved-post-from-a-drop-down-box-not-working-help-me-please/ Share on other sites More sharing options...
ignace Posted August 15, 2009 Share Posted August 15, 2009 $row['$craftsperson_id'] should be: $row['craftsperson_id'] Link to comment https://forums.phpfreaks.com/topic/170422-solved-post-from-a-drop-down-box-not-working-help-me-please/#findComment-898986 Share on other sites More sharing options...
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