Jump to content

Multiple image upload:-

billy_111

By billy_111
in PHP Coding Help

 Share

Recommended Posts

billy_111 Member

billy_111

Posted
Posted

Hey,

 

I am trying to upload a number of images to my server at the same time in the same code, but am having problems. My code is shown below:-

 

	<?php
	if (isset($_POST['btn_update']))
	{
		if($_POST['txt_c_name'] == "" || $_POST['txt_name'] == "" || $_POST['txt_desc'] == "" || $_POST['txt_price'] == "")
		{
		echo "<p style='color:red;padding:4px'>Please fill in all the fields.</p>";
		}
		elseif($_POST['thing'] == "0")
		{
		echo "<p style='color:red;padding:4px'>Please select a category.</p>";
		}
		else
		{				
			include("conn.php");

			$path1= 'garments/'.$_FILES['ufile'][0]['name'];
			$path2= 'garments/'.$_FILES['ufile'][1]['name'];
			$path3= 'garments/'.$_FILES['ufile'][2]['name'];
			$path4= 'garments/'.$_FILES['ufile'][3]['name'];
			$path5= 'garments/'.$_FILES['ufile'][4]['name'];

			copy($_FILES['ufile'][0]['tmp_name'], $path1);
			copy($_FILES['ufile'][1]['tmp_name'], $path2);
			copy($_FILES['ufile'][2]['tmp_name'], $path3);
			copy($_FILES['ufile'][3]['tmp_name'], $path4);
			copy($_FILES['ufile'][4]['tmp_name'], $path5);

			$filesize1=$_FILES['ufile'][0]['size'];
			$filesize2=$_FILES['ufile'][1]['size'];
			$filesize3=$_FILES['ufile'][2]['size'];
			$filesize4=$_FILES['ufile'][3]['size'];
			$filesize5=$_FILES['ufile'][4]['size'];

[u][b]				echo "<pre>";

			print_r($_FILES); [/b][/u]

			$insert = "INSERT INTO category_selection (cat_id, selection_name, item_name, item_description, item_price, main_image, image_1, image_2, image_3, image_4, date_uploaded) VALUES 
			(
			'".$_POST['thing']."', 
			'".$_POST['txt_c_name']."', 
			'".$_POST['txt_name']."', 
			'".$_POST['txt_desc']."', 
			'".$_POST['txt_price']."', 
			$path1,
			$path2,
			$path3,
			$path4,
			$path5,
			now()
			)";
			$add_member = mysql_query($insert);

			if($filesize1 && $filesize2 && $filesize3 && $filesize4 && $filesize5 != 0)
			{
			echo "We have recieved your files";
			}

			else {
			echo "ERROR.....";
			}

			if($filesize1==0) {
			echo "There're something error in your first file";
			echo "<BR />";
			}

			if($filesize2==0) {
			echo "There're something error in your second file";
			echo "<BR />";
			}

			if($filesize3==0) {
			echo "There're something error in your third file";
			echo "<BR />";
			}

			if($filesize4==0) {
			echo "There're something error in your fourth file";
			echo "<BR />";
			}

			if($filesize5==0) {
			echo "There're something error in your fifth file";
			echo "<BR />";
			}
		}

 

If you look at the underlined code, i tried to pull out what the array was returning, when i try to upload i get this message:-

 

Warning: copy() [function.copy]: Filename cannot be empty in /domains/skindeepapparel.com/http/lou/admin.php on line 148

Warning: copy() [function.copy]: Filename cannot be empty in /domains/skindeepapparel.com/http/lou/admin.php on line 149

Warning: copy() [function.copy]: Filename cannot be empty in /domains/skindeepapparel.com/http/lou/admin.php on line 150

Warning: copy() [function.copy]: Filename cannot be empty in /domains/skindeepapparel.com/http/lou/admin.php on line 151

Warning: copy() [function.copy]: Filename cannot be empty in /domains/skindeepapparel.com/http/lou/admin.php on line 152

Array
(
    [ufile] => Array
        (
            [name] => Array
                (
                    [0] => company_profile.jpg
                    [1] => company_profile.jpg
                    [2] => company_profile.jpg
                    [3] => company_profile.jpg
                    [4] => company_profile.jpg
                )

            [type] => Array
                (
                    [0] => image/jpeg
                    [1] => image/jpeg
                    [2] => image/jpeg
                    [3] => image/jpeg
                    [4] => image/jpeg
                )

            [tmp_name] => Array
                (
                    [0] => /tmp/phpk1ayDp
                    [1] => /tmp/phpTwFEKs
                    [2] => /tmp/phpL2Hfmw
                    [3] => /tmp/phpRL2fEA
                    [4] => /tmp/phpI8ctvF
                )

            [error] => Array
                (
                    [0] => 0
                    [1] => 0
                    [2] => 0
                    [3] => 0
                    [4] => 0
                )

            [size] => Array
                (
                    [0] => 6504
                    [1] => 6504
                    [2] => 6504
                    [3] => 6504
                    [4] => 6504
                )

        )

)

 

Sorry for pasting loads of code, but i think it was the best way to explain what i am trying to acheive..

 

Hope someone can help.

 

Regards

 

 

Link to comment
https://forums.phpfreaks.com/topic/170867-multiple-image-upload/
Share on other sites
billy_111 Member

billy_111

Posted
  • Author
Posted

Hey,

 

I have managed to upload the file to the server but i need to add the value to the specific rows in the database. I have 5 image uploads.. Now i have the following code:-

 

			include("conn.php");

			$insert = "INSERT INTO category_selection (cat_id, selection_name, item_name, item_description, item_price, main_image, image_1, image_2, image_3, image_4, date_uploaded) VALUES 
			(
			'".$_POST['thing']."', 
			'".$_POST['txt_c_name']."', 
			'".$_POST['txt_name']."', 
			'".$_POST['txt_desc']."', 
			'".$_POST['txt_price']."', 
			'".$_FILES['ufile']."',
			'".$_FILES['ufile']."',
			'".$_FILES['ufile']."',
			'".$_FILES['ufile']."',
			'".$_FILES['ufile']."',
			now()
			)";
			$add_member = mysql_query($insert);

			//places files into same dir as form resides
			foreach ($_FILES["ufile"]["error"] as $key => $error) 
			{
			   if ($error == UPLOAD_ERR_OK) 
			   {
			       echo"$error_codes[$error]";
			       move_uploaded_file(
			         $_FILES["ufile"]["tmp_name"][$key], 
			         'garments/'.$_FILES["ufile"]["name"][$key]
			       ) or die("Problems with upload");
			   }
			}

 

Take a look at my insert statement, i want it to add each image file, but how can i do this?

 

Regards

 

 

ignace Advanced Member

ignace

Posted
Posted 
if (is_post() && !empty($_FILES)) {
    $files = $_FILES['userfiles'];
    if (is_array($files['tmp_name'])) {
        $sizeof = sizeof($files['tmp_name']);
        for ($i = 0; $i < $sizeof; ++$i) {
            $tmp_name = $files['tmp_name'][$i];
            $name = $files['name'][$i];
            //..
        }
    } else {
        $tmp_name = $files['tmp_name'];
        $name = $files['name'];
        //..
    }
}

function is_post() {
    return 'POST' === $_SERVER['REQUEST_METHOD'];
}

billy_111 Member

billy_111

Posted
  • Author
Posted

Hey,

 

Thanks for that, i have tried with the code in this way:-

 

	<?php
	if (isset($_POST['btn_update']))
	{
		if($_POST['txt_c_name'] == "" || $_POST['txt_name'] == "" || $_POST['txt_desc'] == "" || $_POST['txt_price'] == "")
		{
		echo "<p style='color:red;padding:4px'>Please fill in all the fields.</p>";
		}
		elseif($_POST['thing'] == "0")
		{
		echo "<p style='color:red;padding:4px'>Please select a category.</p>";
		}
		else
		{			
			if (is_post() && !empty($_FILES)) 
			{
			    $files = $_FILES['ufile'];
			    
			    if (is_array($files['tmp_name'])) 
			    {
			       $sizeof = sizeof($files['tmp_name']);
			        for ($i = 0; $i < $sizeof; ++$i) 
			        {
			            $tmp_name = $files['tmp_name'][$i];
			            $name = $files['name'][$i];
			        }
			    } 
			    else 
			    {
			        $tmp_name = $files['tmp_name'];
			        $name = $files['name'];
			    }
			}

			function is_post() {
			    return 'POST' === $_SERVER['REQUEST_METHOD'];
			}

			include("conn.php");

			$insert = "INSERT INTO category_selection (cat_id, selection_name, item_name, item_description, item_price, main_image, image_1, image_2, image_3, image_4, date_uploaded) VALUES 
			(
			'".$_POST['thing']."', 
			'".$_POST['txt_c_name']."', 
			'".$_POST['txt_name']."', 
			'".$_POST['txt_desc']."', 
			'".$_POST['txt_price']."', 
			'".$_FILES['ufile']."',
			'".$_FILES['ufile']."',
			'".$_FILES['ufile']."',
			'".$_FILES['ufile']."',
			'".$_FILES['ufile']."',
			now()
			)";
			$add_member = mysql_query($insert);

			//places files into same dir as form resides
			foreach ($_FILES["ufile"]["error"] as $key => $error) 
			{
			   if ($error == UPLOAD_ERR_OK) 
			   {
			       echo"$error_codes[$error]";
			       move_uploaded_file(
			         $_FILES["ufile"]["tmp_name"][$key], 
			         'garments/'.$_FILES["ufile"]["name"][$key]
			       ) or die("Problems with upload");
			   }
			}
		}
	}
	?>

 

I presumed that where you suggested $files = $_FILES['userfiles']; you were refering to $_FILES['ufile']..?

 

Anyway i receive this error, now the insert AND the upload does not work..

 

Fatal error: Call to undefined function is_post() in /domains/skindeepapparel.com/http/lou/admin.php on line 140

 

Line 140 is the start of the code you suggested:-

 

if (is_post() && !empty($_FILES)) {...

 

Regards

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
 Share
Go to topic listing
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.