[SOLVED] Function variable

[shergold]

Hey guys, i was just wondering if anyone could point me in the right direction. Im trying to update the value of a variable in a function then use it outside of the function , for example;

<?php

function  update(){

$tile = "grass";

}

echo $grass;

?>

 

I have tried using return $grass at the end of the function but it still isnt working.

 

Thanks,

shergold.

[Asheeown]

<?php
function update() {
$tile = "grass";
return $tile;
}

echo update();
?>

[shergold]

it still isnt working, heres my  actual code

 

function tile(){
$tile = "grass";
return $grass;
}



function render($rows = 10 , $cols = 10 , $tileWidth = 50 , $tileHeight = 50 ){
$gameWidth = $cols * $tileWidth;
$gameHeight = $rows * $tileHeight;
$game = "<table frame=\"border\" width=\"$gameWidth\" height=\"$gameHeight\" cellpadding=\"0\" cellspacing=\"0\">\n";
// while there is more tiles to display keep looping
for ($i = 0; $i < $rows; ++$i) {
        $game .= "<tr>\n";
        for ($j = 0; $j < $cols; ++$j) {
		//if user location is equal to tile location display user
		if ($i == $y && $j == $x)
            	$game .= "<td width=\"$tileWidth\" height=\"$tileHeight\" background=\"" . tile() . ".gif\"><img src=\"mod.gif\" alt=\"tile\">\n</td>\n";
		//else display no user
		else 
			$game .= "<td width=\"$tileWidth\" height=\"$tileHeight\" background=\"" . tile() . "gif\">\n</td>\n";

 

if you cant put tile() in the middle of a variable is there anyway i can put the value of tile() in there?

[Asheeown]

function tile(){

$tile = "grass";

return $grass;

}

$t = tile();

 

Why are you returning $grass, that variable doesn't even exist $tile is the actual variable

 

function tile(){
$tile = "grass";
return $tile;
}
$t = tile();

[shergold]

what do you mean? $tile is the variable and grass is the value of the variable.

[mikesta707]

you are returning the wrong variable. the variable $grass is nonexistent in the function, until you return it, which instantiates it with a value of null. You have to return the variable $tile. you function should be

 

function tile(){
$tile = "grass";
return $tile;
}

[shergold]

ahhh sorry lol... see it now hehe, accident.