[SOLVED] IF statement help

[shergold]

Hey guys, I was wondering what is wrong with the following code, it should be executing the code that executes when the if is true, but it is executing the else code. $x and $y variables both equal 0.

 

if (isset($_POST['up']))
{
	$y = $y + 10;

	if (!$y > 100)
		$moved = 1;
	else
		{
			$y = $y - 10;
			echo "You cant move any further forward as you have reached the boundry";
		}
}

 

Thanks,

shergold.

[mikesta707]

if ($y <= 100)

[ignace]

if (!$y > 100) doesn't work because (i'm not sure tough) ! and > share the same execute rights meaning that !$y is executed first and afterwards $y > 100 thus if $y contains a value > 0 then in the context of !$y will return false afterwards in the context of $y > 100 is $y a boolean used in a integer context boolean to integer returns 0 for false 1 for true thus 1 > 100 will return false if (false) executes else.

[shergold]

ok thanks for everyones help, im also having trouble with the following if statement doing the same as the previous:

 

elseif (isset($_POST['down']))
{
	$y = $y - 10;

	if ($y >= 0)
		$moved = 1;
	else	
		{
			$y = $y + 10;
			echo "You cant move any further south as you have reached the boundry";
		}
}

[mikesta707]

Make sure that y is what you expect it to be. That if statement looks fine to me, assuming that you have correct values for $y. try echoing $y before the if statement and see what it is

[shergold]

ah thankyou, yeah $y had a value of 0 .

 

Shergold.