[SOLVED] Move image to folder without move_uploaded_file()

[alemapo]

Hi,

I created my program to upload and move images to the correct folder and it worked great. Then decided to use imagemagick to reduce the size of the image. That also works perfectly through the imagemagick part. Now that I have my reduced image in a variable how do I move that to the correct folder now that I can no longer use move_uploaded_file()?  I have 2 functions - the first one uploads the image, checks the type, etc. The 2nd one does the actual move (and now the resize).  I'm only showing the second one here that deals with the move.  Any help or suggestions would be greatly appreciated!

Pamela

 

function move_image($full_path, $short_path)  {

 

  $original_image =  $_FILES['thefile']['tmp_name'];

 

  $size = GetImageSize($original_image);

   

  $new_image = $_FILES['thefile']['name'];

 

  $max_width = "300";

 

  $max_height = "300";

 

  exec("convert -size {$size[0]}x{$size[1]} $original_image -thumbnail      $max_widthx$max_height $new_image");

 

    echo "<img src=\"".$new_image."\">";

 

 

Note:  Where I have the echo of the image used to be my move_uploaded_file() before I put in the imagemagick.  But the image I want to move is now in $new_image instead of $_FILES['thefile']['tmp_name'] so I'm not sure how to get that in my folder.

 

Thanks in advance if you can help! 

 

[markwillis82]

      exec("convert -size {$size[0]}x{$size[1]} $original_image -thumbnail      $max_widthx$max_height $new_image");

 

add the new absolute directory for new image

 

      exec("convert -size {$size[0]}x{$size[1]} $original_image -thumbnail      $max_widthx$max_height /var/www/html/$new_image");

[alemapo]

Thanks!  That's what I needed!

Pamela