[SOLVED] List Fields Only If They Have A Value

[dwayneparton]

I am new to the forums, and was hoping for some help.

 

I have a php script that prints all the fields and values of an e-form when submitted. Here is what I basically have.

 

foreach($_POST as $field => $val)

{

$message = $message . trim($field)." = ". trim($val). "\n" ;

}

 

What I want is for the script to only list the fields if they have a value. If someone, for instance, leaves one of the input boxes empty then it doesn't show up in the email unless it has a default value. Hope that makes sense.

Please Help.

[ignace]

print !empty($val) ? $message . trim($field)." = ". trim($val). "\n" : '';

[dwayneparton]

Thanks for the reply. I thought I would be able to figure out how to use the answer with my code, but I can not. Here is what all of my code looks like.

 

foreach($_POST as $field => $val)

{

if($i%2 == 0){$message = $message.'<tr bgcolor="#E9EDF5"><td valign="top"><b>'.trim($field).'</b></td><td>'.trim($val).'</td></tr>' ;

$i++; }

else{$message = $message.'<tr><td valign="top"><b>'.trim($field).'</b></td><td>'.trim($val).'</td></tr>' ;

$i++;}

}

 

My boss wanted the emails to come out in pretty HTML. Sorry for the lack of detail the first time.

Thanks for the Help.

[lemmin]

You don't have to do it as an inline if. You can just do it like this:

 

foreach($_POST as $field => $val)
   {
       if (!empty($val))
      {
      if($i%2 == 0){$message = $message.'<tr bgcolor="#E9EDF5"><td valign="top"><b>'.trim($field).'</b></td><td>'.trim($val).'</td></tr>' ;
      $i++; }
      else{$message = $message.'<tr><td valign="top"><b>'.trim($field).'</b></td><td>'.trim($val).'</td></tr>' ;
      $i++;}
      }
   }

[dwayneparton]

Worked perfectly! THANKS!