Passing variable through REQUIRE for a cron job

[edhkirk]

I am trying to execute the following command in a php file:

 

require("/home/content/*myserver/kithomegreen/wp-content/plugins/wp-o-matic/cron.php?code=f988040a");

 

But I get the error:

 

"failed to open stream: No such file or directory"

 

When I remove the question mark, it executes fine but does not pass the variable code.

 

Do I need to change the syntax for the question mark, or is there another way to pass the code to the next file?

[fooDigi]

since your php file is including cron.php... just set a variable before you include it, and it will be accessible...

 

$code="f988040a";
require("/home/content/*myserver/kithomegreen/wp-content/plugins/wp-o-matic/cron.php");

 

and you will be able to reference "$code" from within cron.php

 

 

[edhkirk]

I tried this and it did not seem to work.

 

Is it possible that the cron.php code went to look for the variable "code" in the query again, and failed to find it?  Thus it overwrote the value or set it to null.

 

 

[edhkirk]

Here is the code for the cron.php:

 

<?php

 

require_once(dirname(__FILE__) . '/../../../wp-config.php');

                                   

nocache_headers();

 

// if uninstalled, let's not do anything

if(! get_option('wpo_version'))

  return false;

 

// check password

if(isset($_REQUEST['code']) && $_REQUEST['code'] == get_option('wpo_croncode'))

{

require_once( dirname(__FILE__) . '/wpomatic.php' );

 

$wpomatic->runCron();

} else                                                                         

    $wpomatic->log('Warning! cron.php was called with the wrong password or without one!');