the magus Posted September 1, 2009 Share Posted September 1, 2009 Hello everybody I am using a very simple PHP upload script.. and I have 2 domains... domain1.com & domain2.com domain1.com is the main domain which is linked to the root. While domain2.com is linked to a folder ("up" for example) inside public_html I am using my php upload script on domain2.com. After uploading files script displays the link of the uploaded files as this: h ttp:// www .domain1. com /up/ uploaded/ image.jpg WHAT I WANT is to make the script display domain2.com not the main domain which is linked to the root. i.e i want to make the link as this (h ttp:// www .domain2 .com/ uploaded/image.jpg and here is the code: include_once("header.php"); // load main switch if constant pass is defined if(defined("DODOUPLOADOK")) { switch($action) { case "uploadmulti_upload": case "upload": $uploaded_files = handle_uploaded_files("userfile"); if(empty($uploaded_files)) { print_error("عملية خاطئة", "لم تقم تقم برفع أي ملف أو ملفات"); } else { $error = uploadfiles_error_checking($uploaded_files, $userpath, $MAX_FILE_SIZE, $dim_requirement, $require_exact_dim, $filename_limit, $require_file_type); if($error !== true) print_error("Error", $error); else { $output = upload_files($uploaded_files, $userpath); print_error("تم تحميل الملف بنجاح", "رابط الملف الذي تم تحميلة.<br /><br />".$output, "العودة للملفات ", $_SERVER['PHP_SELF']); display_upload_form(); } and I think the problem is here: $output = upload_files($uploaded_files, $userpath); print_error("تم تحميل الملف بنجاح", "رابط الملف الذي تم تحميلة.<br /><br />".$output, "العودة للملفات ", $_SERVER['PHP_SELF']); display_upload_form(); } I hope I could cleared my point. Thanks in advance Link to comment https://forums.phpfreaks.com/topic/172715-display-uploaded-files-change-link/ Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.