<form action= > problem

[robert_gsfame]

if((!empty($_POST['title'])) && (!empty($_POST['text']))){

$check="success.php";}else{

$check="failed.php";}?>

 

<form method = "post" action="<?php echo $check;?>">

 

Which part is wrong as i always go to failed.php although both text and title are not empty

 

i've tried with !isset but it didn't work either...need someone suggestion..

 

Thanks in advance

[Bricktop]

Hi robert_gsfame,

 

action= will always be "failed.php" because the action= attribute is taken from the moment you press the "Submit" button.

 

Because PHP is server-side, the PHP code you posted does not get processed until after the "Submit" button has been pressed.

[robert_gsfame]

yeah i know..i've put the submit button, once clicked then it goes to failed.php although i've made a condition using IF

[PFMaBiSmAd]

although both text and title are not empty

 

Prove it. What do you get when you use the following -

 

echo "<pre>",print_r($_POST,true),"</pre>";

[lihman]

Try this:

 

Make a new file called action.php and in it place the following code:

 

<?php
if((!empty($_POST['title'])) && (!empty($_POST['text']))){
      INSERT INTO HERE WHATEVER IS IN success.php (excluding <?php and ?>) ;
} else {
      INSERT INTO HERE WHATEVER IS IN failed.php (excluding <?php and ?>) ;
}
?>

 

Change the code on the form to this:

 

<form method="POST" action="action.php">

 

Maybe you should try that