return a dynamic field value

[SystemOverload]

PHP 5.2.5

 

Inside a PHP function, I've returned a set of results from a table, there will only ever been one record.

 

while ($arrAccVerify = mysql_fetch_array($rsAccVerify)) { 
$fldContactName = $arrAccVerify['contact_name']; 
return $fldContactName;
}

 

but what if I want to return a dynamic field, ie, the field of choosing at the time i call the function, ie:

 

$varReturnField = "contact_email";

while ($arrAccVerify = mysql_fetch_array($rsAccVerify)) { 
$fldReturnField= $arrAccVerify['$varReturnField']; 
return $fldReturnField;
}

 

I tried this and i just get [Notice: Undefined index: $varReturnField]... Is what I am trying to achieve possible, and if so, how???

 

Thanks

[rhodesa]

get rid of the single quotes:

$varReturnField = "contact_email";

while ($arrAccVerify = mysql_fetch_array($rsAccVerify)) {
   $fldReturnField= $arrAccVerify[$varReturnField];
   return $fldReturnField;
}

[SystemOverload]

LMAO - Thanks... I didn't even think about something as simple as that...

 

Who's a moron....  >>ME<<

 

Thank you...

[rhodesa]

you could have saved yourself a bunch of typing and just used the emoticon: