Posting AJAX variables to PHP script

KevMart · September 4, 2009

Hi

This should be pretty simple since I have seen a lot of sites doing this.

Can someone see where I am going wrong for posting AJAX variables to a PHP script? I think there is something wrong in the way I am passing the variables to PHP because when the AJAX variables are passed to the process.php script - and I try get them via the $_POST array - the $_POST array's count is 0 (i.e. zero, and I have tested this a number of times), so the die() command is always run. How can I correctly pass the variables from javascript to PHP? I am using jQuery !!!!

NOTE that I have tested that the AJAX script does retrieve the correct values because an alert command has proved that.

Below you will find some sample code for the various files.

index.php

<html>
<body>
<form method="post" name="searchform">
<table width="100%">
    <tr>
        <td>Select a table</td>
        <td><input type="text" name="table" id="table" /></td>
    </tr>
    <tr>
        <td>Enter username</td>
        <td><input type="text" name="username" id="username" /></td>
    </tr>
    <tr>
        <td><a href="javascript:void(null);" id="searchbutton">Search</a></td>
    </tr>
</table>
</form>
</body>
</html>

AJAX sample code

<script type="text/javascript">
function actionOnUser(php_script_url,adminaction,uname) {
    // create new script element, set its relative URL, and load it
    script = document.createElement( 'script' );
    script.src = php_script_url+adminaction+".php";
    document.getElementsByTagName( 'head' )[0].appendChild( script );
    alert(adminaction+" action on "+ uname +" still needs to be coded by "+script.src);
}

$(document).ready(function() {
    $("#searchbutton").click( function (eventObject) {
        var uname = $("#username").val();
        var tablename = $("#table").val();

        if(tablename == "")
            alert("Please select a table!");
        else
        {
            var protocol = window.location.protocol;
            var host = window.location.hostname;
            var url = protocol+'//'+host+'/process.php';

            $.post(url,{nickname:uname,table:tablename},function(data) {
                var eval = $.evalJSON(data);
                $('#viewform').append(eval.result);
                $('#viewform').show();
            });
            return false;
        }
    });
    $('#cancelbutton').click( function() {
        $('#viewform').hide();
    });
});

process.php

<?php
if(count($_POST) == 0) die("post array is empty");

mysql_connect('localhost','user','password');
mysql_select_db('database');

function performAdminQuery($table,$uname)
{
    $qry = "SELECT * FROM $table";

    if($uname != "")
        return array(mysql_fetch_assoc(mysql_query($qry." WHERE nickname='$uname'")));

    $result = mysql_query($qry);
    $num_rows = mysql_num_rows($result);

    $info = array();
    for($i=0;$i<$num_rows;$i++)
    {
        $data = mysql_fetch_array($result);
        
        $info[$i]['nickname'] = $data['nickname'];
        $info[$i]['email'] = $data['email'];
        $info[$i]['firstname'] = $data['firstname'];
        $info[$i]['lastname'] = $data['lastname'];
        $info[$i]['gender'] = $data['gender'];
        $info[$i]['birth'] = $data['birth'];
        $info[$i]['time_stamp'] = $data['time_stamp'];
    }

    return $info;
}

$uname_array = json_decode($_POST['uname'],true);
$table_array = json_decode($_POST['tablename'],true);

$uname = $uname_array['nickname'];
$table = $table_array['table'];

$adminpanel = performAdminQuery($table,$uname);

$res["result"] = $adminpanel;
echo json_encode($res);
?>

Sign In

Posting AJAX variables to PHP script

Recommended Posts

KevMart

Link to comment

Share on other sites

Join the conversation

Browse

Activity

Important Information