Order() code fix.

[k0z]

Hi, This is my current code:

 

<?php

 

 

$favorites=2;

$recent=1;

 

 

$given_array = array("favorites"=>$favorites, "recent"=>$recent);

$abc = order_array($given_array);

 

function order_array ($given_array) {

 

 

sort($given_array);

 

foreach($given_array as $key => $value) {

echo $value . ':';

  }

 

}

 

?>

 

This code returns "1:2:"

The problem is, this is returning the values of the strings that were defined at the top of the code. Instead of returning their values, i want it to return their names. So in this case, it would return "recent:favorites:"

How do i do this?

 

Thanks.

[Alex]

You want to echo the keys of the array? Or the names of the variables? In this case they would be the same..

 

echo $key . ':';

[k0z]

You want to echo the keys of the array? Or the names of the variables? In this case they would be the same..

 

echo $key . ':';

I tried doing that, however this just returns "0:1:" . I guess sort() removes the keys i defined, and turns it into numerical values.

[k0z]

Nevermind. all i need to do is use asort.