shark1234 Posted September 22, 2009 Share Posted September 22, 2009 Hello, I was just looking for help on how to make an XHR Request to work using to file. I have it working for one file title.php but i cant seem to figure out how to use 2 files if anyone has an idea can you please let me no Thanks alot <script type="text/javascript" src="zxml.js"></script> <script type="text/javascript"> function getRequest() { var oXmlHttp = zXmlHttp.createRequest(); oXmlHttp.open("get","title.php",true); oXmlHttp.onreadystatechange = function () { if (oXmlHttp.readyState == 4) { if (oXmlHttp.status == 200) { displayCustomerInfo(oXmlHttp.responseText); } else { displayCustomerInfo("An error occurred: " + oXmlHttp.statusText); //statusText is not always accurate } } } oXmlHttp.send(null); } function displayCustomerInfo(sText) { var divCustomerInfo = document.getElementById("put_here"); divCustomerInfo.innerHTML = sText; } </script> </head> <body> <br /> <div id="put_here">Click Above to see the time</div> <br /> <div id="theTime">Click Above to see the time</div> </body> </html> Link to comment https://forums.phpfreaks.com/topic/175059-new-to-ajax/ Share on other sites More sharing options...
RichardRotterdam Posted September 22, 2009 Share Posted September 22, 2009 Format your code between these you could just add a param to the getRequest() function function getRequest(url) { var oXmlHttp = zXmlHttp.createRequest(); oXmlHttp.open("get",url,true); // use the url var here // the rest of the function } Link to comment https://forums.phpfreaks.com/topic/175059-new-to-ajax/#findComment-922874 Share on other sites More sharing options...
shark1234 Posted September 22, 2009 Author Share Posted September 22, 2009 Thanks alot! illl play around with that and see what i can do Link to comment https://forums.phpfreaks.com/topic/175059-new-to-ajax/#findComment-923094 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.