space every 3 characters

[smerny]

lets say i have the binary 1011101.1011

 

how could i take that, and print this:

 

001 011 101 . 101 100

 

notice it adds 0s on the ends if it needs to and leaves the decimal alone

 

[redarrow]

<?php

$num="1011101.1011";

$test=wordwrap($num,3,"\n", true);

echo $test;
?>

 

http://uk.php.net/manual/en/function.wordwrap.php

[smerny]

that doesn't solve the problem with adding 0's on the ends and it does not work with the decimal points

[redarrow]

what you on about ......

 

 

do you want the last two 11 into 00

 

 

[smerny]

example input: 1011101.1011

 

example output: 001 011 101 . 101 100

[redarrow]

HOW ARE YOU DETERMINING THAT A 00 IS NEEDED FOR THE END......

 

sorry my magic crystal ball broke...

[redarrow]

example....

 

if the format of the number has 11 at the end add two 00 ,

 

or if there 101 first three numbers add the two 00 at the end,

tel us then

[smerny]

groups of 3 digits... if it does not amount to 3 digits at the ends, add 0's to make it that way (working away from the decimal point)

 

so 1 011 101 . 101 1

becomes 001 011 101 . 101 100

 

have you ever converted binary to octal by hand? this is the first step

[Garethp]

This is what I came up with

 

<?php

$test="1011101.1011";

for($i=0;$i<strlen($test);$i++)
{
$testa[] = $test[$i];
}

$test = "";
$i = 1;
foreach($testa as $k=>$v)
{
if($v == ".")
	{
	$test .= " . ";
	$i = 1;
	continue;
	}
else
	{
	$test .= $v;
	}

if($i == 3)
	{
	$i = 0;
	$test .= " ";
	}
$i++;
}

$test = split(" ", $test);
foreach($test as $k=>$v)
{
if($v == ".")
	{
	continue;
	}

while(strlen($test[$k])<3)
	{
	$test[$k] .= "0";
	}
}
$test = join(" ", $test);

print_r($test);
?>

[redarrow]

i was rude deleted(( taking the pain like a man))

[Garethp]

Redarrow, must you be so rude? He posted what he wanted in the first post

 

"notice it adds 0s on the ends if it needs to and leaves the decimal alone";

 

The time in which you speant being rude I came up with actual working code, quite unlike you. You might want to try some courtesy, or GTFO

[redarrow]

if the format changes will it still work?

 

i was not being rude i was simple asking for the format off the numbers...

 

if the numbers are in a special format permanently then it a easy solution?

 

if the numbers continue to change and the format needs to change then it not so easy to get the correct result.

 

example if the binary number get smaller your code does nothink...

[smerny]

yea red didn't make much sense asking for examples when i gave examples...

 

garethp, at first i thought yours was working, but i got this:

 

input: 11010111.1011

output: 110 101 110 . 101 100

 

it should be instead: 011 010 111 . 101 100

[smerny]

another example of output from your code garethp

 

input: 1101.1011

output: 110 100 . 101 100

 

i think i see what it's doing, it is adding the 0's to the wrong side of the digits to the left of the decimal... working well on the right side of the decimal though

[redarrow]

Redarrow, must you be so rude? He posted what he wanted in the first post

 

"notice it adds 0s on the ends if it needs to and leaves the decimal alone";

 

The time in which you speant being rude I came up with actual working code, quite unlike you. You might want to try some courtesy, or GTFO

 

thort it was working?

 

 

WHALE WERE ALL GETTING FORMATS I WONDER WHY

[Garethp]

Could you explain why it would be that? If you take your input string, and put a space every third letter, it goes like this

 

110 10111.1011

110 101 11.1011

110 101 11 . 1011

110 101 11 . 101 1

 

And then you put a 0 at the end of the groups that are less than three

 

110 101 110 . 101 100

 

And you show us how it should work, how the code should reach it's output?

[Alex]

Hm, I came up with something myself..

 

Edit: Fixed it.

 

<?php
$str = '1011101.1011';
$split = str_split($str);
$num_len = count($split) - cc('.', $split);
$num_before = array_search('.', $split);
$num_after = $num_len - $num_before;

if($num_before % 3 != 0)
$str = implode(array_fill(0, 3 - $num_before % 3, 0)) . $str;
if($num_after % 3 != 0)
$str .= implode(array_fill(0, 3 - $num_after % 3, 0));

$split = str_split($str);
for($i = 0;$i < count($split);$i++)
if($split[$i] == '.')
	$split[$i] = ' . ';
else if($i % 4 == 0)
	array_splice($split, $i, 0, ' ');

echo implode($split);

function cc($char, $arr)
{
$num = 0;
foreach($arr as $part)
	if($part == $char)
		$num++;
return $num;
}
?>

[smerny]

I don't know how the code should reach the output or I wouldn't be here.

 

but do you know binary numbers?

 

001 and 1 are the same thing, 100 and 1 are not

 

1.1 and 001 . 100 are the same

 

100 . 100 are not

 

 

splitting it into sets of 3 allows it to be more easily seen as octals is all

[Garethp]

Here

 

<?php

$test="1011101.1011";

while(!str_replace(".", "", $test) % 3)
{
$test = "0" . $test;
}

for($i=0;$i<strlen($test);$i++)
{
$testa[] = $test[$i];
}

$test = "";
$i = 1;
foreach($testa as $k=>$v)
{
if($v == ".")
	{
	$test .= " . ";
	$i = 1;
	continue;
	}
else
	{
	$test .= $v;
	}

if($i == 3)
	{
	$i = 0;
	$test .= " ";
	}
$i++;
}

$test = split(" ", $test);
foreach($test as $k=>$v)
{
if($v == ".")
	{
	continue;
	}

while(strlen($test[$k])<3)
	{
	$test[$k] .= "0";
	}
}
$test = join(" ", $test);

print_r($test);
?>

 

Also, redarrow, only post if you have something useful to contribute

[smerny]

Thanks guys, got it working now

[redarrow]

alexWD fixed it and works perfect...

[smerny]

yes I used alexWD's example and it put the 0's in the right spots and everything... i just had to tweak it here:

 

foreach($arr as $part)
  if($part == $char)
    $num++;

 

into:

foreach($arr as $part)
{
  if($part == $char)
    $num++;
}

 

 

garethp had a good idea also and was on the right track, but i just kept getting 0's added directly to the left of the decimal instead of way at the left end

[Alex]

yes I used alexWD's example and it put the 0's in the right spots and everything... i just had to tweak it here:

 

foreach($arr as $part)
  if($part == $char)
    $num++;

 

into:

foreach($arr as $part)
{
  if($part == $char)
    $num++;
}

 

 

garethp had a good idea also and was on the right track, but i just kept getting 0's added directly to the left of the decimal instead of way at the left end

 

That shouldn't cause a difference because there's only 1 expression being evaluated there.

[redarrow]

alexWD code was well hard to understand. but i got there in the end, what i done is shine it on my projector and walked with my wight stick and pointed at the huge code until i understood it....

 

maybe in 10 years time ill code like that....

[Alex]

I'm about to head off to bed in a little bit (After I finish working on something..) But if you want I'll break it down and explain it part by part.