kool_samule Posted October 12, 2009 Share Posted October 12, 2009 Hi Chaps, I have a query that searches through 3 tables and displays the results for Open Jobs for a specific customer: $colname_rsOpen_Cust = "-1"; if (isset($_GET['id'])) { $colname_rsOpen_Cust = $_GET['id']; } mysql_select_db($database_conndb2, $conndb2); $query_rsOpen_Cust = sprintf("SELECT* FROM(( SELECT tbl_projects.projid, tbl_projects.projtype, tbl_jobs.jobname, tbl_jobs.jobid, tbl_jobs.jobwnet, tbl_jobs.jobprepared, tbl_jobs.jobtranscomplete, tbl_jobs.jobftype, tbl_jobs.jobcorrec, tbl_jobs.jobcordoc, tbl_jobs.jobshipped, tbl_customers.custid, tbl_customers.custname, tbl_languaget.langtname FROM tbl_projects INNER JOIN tbl_jobs ON tbl_projects.projid=tbl_jobs.FK_projid INNER JOIN tbl_customers ON tbl_customers.custid=tbl_projects.FK_custid INNER JOIN tbl_languaget ON tbl_languaget.langtid=tbl_jobs.FK_langid ) UNION ( SELECT tbl_projects.projid, tbl_projects.projtype, tbl_jobtransline.jobname, tbl_jobtransline.jobid, tbl_jobtransline.jobwnet, tbl_jobtransline.jobaccepted AS jobprepared, tbl_jobtransline.jobtranscomplete, tbl_jobtransline.jobftype, tbl_jobtransline.jobcorrec, tbl_jobtransline.jobcordoc, tbl_jobtransline.jobshipped, tbl_customers.custid, tbl_customers.custname, tbl_languaget.langtname FROM tbl_projects INNER JOIN tbl_jobtransline ON tbl_projects.projid=tbl_jobtransline.FK_projid INNER JOIN tbl_customers ON tbl_customers.custid=tbl_projects.FK_custid INNER JOIN tbl_languaget ON tbl_languaget.langtid=tbl_jobtransline.FK_langid ) UNION ( SELECT tbl_projects.projid, tbl_projects.projtype, tbl_jobxml.jobno AS jobname, tbl_jobxml.jobid, tbl_jobxml.jobwnet, tbl_jobxml.jobdownload AS jobprepared, tbl_jobxml.jobtranscomplete, tbl_jobxml.jobftype, tbl_jobxml.jobcorrec, tbl_jobxml.jobcordoc, tbl_jobxml.jobshipped, tbl_customers.custid, tbl_customers.custname, tbl_languaget.langtname FROM tbl_projects INNER JOIN tbl_jobxml ON tbl_projects.projid=tbl_jobxml.FK_projid INNER JOIN tbl_customers ON tbl_customers.custid=tbl_projects.FK_custid INNER JOIN tbl_languaget ON tbl_languaget.langtid=tbl_jobxml.FK_langid )) SomeAlias WHERE custid = %s AND jobshipped='n'", GetSQLValueString($colname_rsOpen_Cust, "int")); $rsOpen_Cust = mysql_query($query_rsOpen_Cust, $conndb2) or die(mysql_error()); //$row_rsOpen_Cust = mysql_fetch_assoc($rsOpen_Cust); $totalRows_rsOpen_Cust = mysql_num_rows($rsOpen_Cust); What I need is a COUNT of all the "jobid". I've tried a few ways but e.g., if there are 6 open jobs in total, for some reason by COUNT shows 3 ?! Quote Link to comment https://forums.phpfreaks.com/topic/177414-solved-count-through-3-tables/ Share on other sites More sharing options...
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