Filtering for a phrase using pregmatch

[greenheart]

Here is my code which looks for addresses which start with ' src=" '

 

preg_match_all('#src="(http://[^"]+)#', $value, $matches)

 

I want to modify this so that it only returns matches which contain the phrase "pass". So src="http://www.example.com/blah/pass/edu" would be picked up.

 

Can someone kindly tell me how to do this? Thank you so much.

[mrMarcus]

have you looked into the preg_match() function at all?  i'm assuming you didn't write the code you provided otherwise you'd know how this is done.

 

are you going to need to match it several times in a string, or just stop once (if) it's matched.

 

if the latter of the two, just use preg_match() .. that site is your new PHP bible.

 

go to that link, and try out the examples .. come back with your attempts, and i'll help clean anything up (if necessary).

[greenheart]

Hello, I have tried with this and variants but no success

 

preg_match_all('#src="(http://[^"]+)#', $value, $matches)

$i=0;
for ($i = 0; $i < 10; $i++){
preg_match_all('#pass#',$matches[i], $result)

print_r($result)

}

 

The idea is stop once I have a match.

 

Could you help me please?

[thebadbad]

Something like

 

<?php
preg_match_all('~\bsrc\s?=\s?([\'"])(http://.+?)\1~is', $value, $matches);
foreach ($matches[2] as $url) {
if (strpos($url, 'pass') !== false) {
	echo "Match found: $url";
	break;
}
}
?>

 

You can use stripos() if the search should be case insensitive.

[mrMarcus]

use preg_match and not preg_match_all, since you do not need to continue searching after a match has been made/found.

[greenheart]

Thanks everyone I figured it out. I used the strpos that thebadbad gives in his code and put it in my code and it works.