weemee500 Posted October 20, 2009 Share Posted October 20, 2009 Hi, I am currently trying to make a part for my user driven website where one user can subscribe to another and whoever they have subscribed to is echoed back on there profile page. my users table structure is: id username password and my subscription table is: id user_id follow_id i am currently trying to query the logged in users subscriptions with this sql_query $subsQuery = mysql_query("SELECT U.username FROM users AS U INNER JOIN subscription AS Sub.follow_id=U.id WHERE Sub.user_id=".$ID); $ID being the logged in users id. However when trying to echo this on the page using this bit of php: <? while ($subs = mysql_fetch_assoc($subsQuery)) { ?><br /><br /> <? echo $subs['username'] ?> <? } ?> it throws back this error: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/avince/public_html/users/user.php on line 53 Any help would be much appreciated! Link to comment https://forums.phpfreaks.com/topic/178327-querying-info-from-one-table-based-on-info-in-another/ Share on other sites More sharing options...
Mchl Posted October 20, 2009 Share Posted October 20, 2009 That's because your query is full of syntax errors. It should go something like this SELECT U.username FROM users AS U INNER JOIN subscription AS Sub ON (Sub.follow_id=U.id) WHERE Sub.user_id=$ID Link to comment https://forums.phpfreaks.com/topic/178327-querying-info-from-one-table-based-on-info-in-another/#findComment-940303 Share on other sites More sharing options...
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