Displaying Values of an Array in Table

[surajkandukuri]

Hi,

 

  I have few arrays namely

firstarray(),secondarray(),thirdarray() which are computed based on some php query results.

 

Now I want to display the results of each in a table format for example

 

  FIRST COLUMN      SECOND COLUMN    THIRD COLUMN

  firstarray(1)          secondarray(1)      thirdarray(1)

  firstarray(2)          secondarray(2)      thirdarray(2)

............. and so on .

 

How to achieve this, The number of rows in the table should be dependent on the number of values in the array.

 

  Please tell me how to achieve this...

 

 

 

 

[mikesta707]

are the lengths the same? and are they numeric? if so you can do something like

echo "<table>"
for ($i = 0; $i < count($firstarray); $i++){
echo "<tr>";
echo "<td>".$firstarray[$i]."</td>";
echo "<td>".$secondarray[$i]."</td>";
echo "<td>".$thirdarray[$i]."</td>";
echo "</tr>";
}
echo "</table>";

[xtopolis]

mikesta707's solution won't show all results if arrays 2 or 3 have more elements than array 1.

 

A "quick" fix would be to change the second line to

$max = max(count($firstarray), count($secondarray), count($thirdarray));
for ($i = 0; $i < $max; $i++){

However, you should also add in code to check that the index is not out of range when it goes to print the values in lines 4,5,6...

[mikesta707]

thats why i asked if they were the same length. Also, you need to make sure the arrays aren't associative, because if so, the solution will be much more complicated