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i have this code below and nothing shows up not even the else statements

<?php
error_reporting(E_ALL);
$connect = mysql_connect("localhost","**********","**********") or die(mysql_error());
if ($connect) {
$select = mysql_select_db("site") or die(mysql_error());
	if ($select) {
	$test = mysql_query("INSERT INTO `site`.`quotes` (`id`, `name`, `email`, `phone`, `type`, `budget`, `start`, `info`, `ip`, `time`) VALUES (NULL, \'1\', \'1\', \'1\', \'1\', \'1\', \'1\', \'1\', \'1\', \'1\')" or die(mysql_error());
	if($test) {
		echo 'yes';
	} else {
		echo 'no';
	}
} else {
	echo "couldnt find db";
}
} else {
echo "couldnt find server";
}
?>

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https://forums.phpfreaks.com/topic/178412-solved-mysql-post-from-php/
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The posted code contains a fatal parse error because of a missing ) on the mysql_query(... statement.

 

Putting error_reporting/display_error settings in your script won't help show fatal parse errors because your code is never executed. You should be developing php code and debugging php code on a system with error_reporting/display_errors set in your php.ini. When we suggest putting lines of code in to set those two settings in your code, it is to debug code that is at least doing something/being executed.

This thread is more than a year old. Please don't revive it unless you have something important to add.

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