Values disappear from my array :( HELP!

[martin729]

hey all, I have a lil mysql/php/apache script that queries a database

and pulls put 5 integers.

 

These 5 integers are then displayed in an HTML table

 

<?php
$i=0;
global $Val_Store;
while ($i < $num) {

$f1=mysql_result($result,$i,"Changes");
$f2=mysql_result($result,$i,"Disposition");

?>

<tr>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td>

</tr>

<?php

$Val_Store[i] = $f1;

$i++;
echo $Val_Store[i] . "-> Val_STORE" . $i . "<br />";
}

 

 

This is just a snippet.

But what is happening is:

A while loop is going through the rows of results obtained from the query, placing the values in temporary variables f1 and f2 (f1 are my integers of interest), and using f1 and f2 to fill the HTML table like this:

<td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td>

 

BUT what i am also doing is storing the temporary values in f1 in the array $Val_Store

$Val_Store[i] = $f1;
$i++;

 

And then printing them ....

 

echo $Val_Store[i] . "-> Val_STORE" . $i . "<br />";

 

 

 

Leaving me with

84-> Val_STORE1

114-> Val_STORE2

99-> Val_STORE3

77-> Val_STORE4

5-> Val_STORE5

 

 

WHICH IS SUPER!

 

 

BUT if i try executing the following code in other sections of my script....

 

<?
echo "DEBUG " . $Val_Store[2] . " DEBUG";
?>

 

...the arrays appears to be empty. Surely it should have spat out element number 2!!

 

Output:

DEBUG DEBUG

          ^

 

 

 

Can anyone help me keep my array elements??

 

Many Thanks

Martin

[kickstart]

Hi

 

You need an extra $ sign in a few places. Eg:-

 

$Val_Store[$i] = $f1;

 

All the best

 

Keith

[taquitosensei]

echo "DEBUG " . $Val_Store[2] . " DEBUG";

actually that would spit out the 3rd element.  Arrays start with zero.

 

you could do

print_r($Val_Store);

  that will give you a better idea of what's in the array.