[SOLVED] Array Error?

[kaveman50]

Does anyone know what's wrong with this array?It says that there is an error on line 19.Basically, I'm trying to make it so that a user enters a name, and it spits out if their name is in the list.  If it's not, it'll say "Not found."

<form method="post" action=""> Name: <input type="text" name="num1" size="10"/><br /><br /><input type="Submit" name="Submit" value="Look up name" /></form>

<?

$name=$_POST['num1'];$array=array('Al', 'David' ,'Sarah' ,'Don' ,'Ed' ,'Bob' ,'Frank', 'Hank', 'Jim' ,'Ben');  for($i=0; $i<=9; $i++){

if ($array[$i]==$name){echo "Found";}else[echo "Not found";]}?>

[kaveman50]

Oh yeah, and how do I make it so that the php code doesn't show up all black on my post?

[Alex]

You're using square brackets where you should be using curly ones in the else statement. There's also no need for a loop, just use in_array()

 

Ex:

if(in_array($name, $array))
{
     echo "Found";
}
else
{
     echo "Not Found";
}

 

This can also be shortened to (using the Ternary Operator):

echo (in_array($name, $array)) ? 'Found' : 'Not Found';

 

To post code use [ code ] or [ php ] tags (without the spaces). If you don't know what I'm talking about press quote on my post to see what it looks like.

[kaveman50]

Now it's saying line 35?

<form method="post" action="">
Name: <input type="text" name="num1" size="10"/>
<br />
<br />
<input type="Submit" name="Submit" value="Look up name" />
</form>



<?

$name=$_POST['num1'];
$array=array('Al', 'Bob', 'Carl','Don' ,'Eric' ,'Fred' ,'Greg', 'Hank', 'Irene' ,'Judy');

for($i=0; $i<=9; $i++){

if(in_array($name, $array))
{
     echo "Found";
}
else
{
     echo "Not Found";
}

?>

 

[mrMarcus]

you're not closing your for() loop.

 

and if your code was any larger than it is now, i wouldn't have even looked at it since 'Now it's saying line 35?' doesn't really mean anything to me other than 'Now it's saying line 35?'.

[Alex]

And as I said before you can completely remove that loop, it's unnecessary.

[kaveman50]

I see your point mrMarcus.  I completely forgot that the lines weren't numbered when i posted my code.

 

 

Alright, so I removed the loop and changed my if statement, but now it is saying that i have an error on this line.

 if(in_array($name, $array))

 

[mrMarcus]

what does the error say

[Alex]

There's nothing wrong with that line assuming those are the correct variables. You really need to post the entire section in question.

[kaveman50]

I don't think it's going to help but it just says

 

Parse error: syntax error, unexpected T_IF in /Applications/XAMPP/xamppfiles/htdocs/webalizer/search_array.php on line 17

[kaveman50]

 

 

<form method="post" action="">
Name: <input type="text" name="num1" size="10"/>
<br />
<br />
<input type="Submit" name="Submit" value="Look up name" />
</form>



<?

$name=$_POST['num1'];
$array=array('Al', 'Bob', 'Carl','Don' ,'Eric' ,'Fred' ,'Greg', 'Hank', 'Irene' ,'Judy');

c

if(in_array($name, $array))
{
     echo "Found";
}
else
{
     echo "Not Found";
}

?>

[akitchin]

... what is that lonely "c" doing right in the middle of that section? that's why the T_IF is unexpected - it is tripping up when you just tell it to do "c" especially without a semicolon.

[mrMarcus]

I don't think it's going to help but it just says

 

Parse error: syntax error, unexpected T_IF in /Applications/XAMPP/xamppfiles/htdocs/webalizer/search_array.php on line 17

of course it helps .. without it, it becomes a guessing game.  the error states the exact issue at hand, 'unexpected T_IF'.  make sure to always post error messages exactly as seen on screen to get more direct assistance.

 

it's like going into the doctors, saying 'fix me doc', and when asked what the error is, you say, 'it won't help'.

[kaveman50]

Thanks akitchin! After I deleted that, it worked.  I don't know why I had that in there.

[kaveman50]

Thanks everyone