array_diff saying no difference when there is

[glenelkins]

hi

 

i got 2 arrays:

 

$array1 = array ( '0' => 'gary' );
$array2 = array ( '0' => 'gary', [1] => 'bakewell' );

if ( !array_diff ( $array1, $array2 ) ) {
   die ( 'no difference' );
} else {
    die('different');
}

 

its coming back saying the arrays are no different, when they clearly are!

[seanlim]

According to PHP.net, the array_diff function "Returns an array containing all the entries from array1 that are not present in any of the other arrays."

 

You will need to reverse array2 and array1 to see any visible results.

[glenelkins]

ok thanks. do you know , to save me looking it up if there is a function to check if there are 1 or more items from the first array, in the second?

[seanlim]

just reverse the array_diff() parameters.

 

are you looking for something like this?

array_merge(array_diff($array1, $array2), array_diff($array2, $array1))

[glenelkins]

what i want

 

$array1 = array ( '0' => 'gary', [1] => 'someone', [2] => 'bakewell' );

$array2 = array ( '0' => 'gary', [1] => 'bakewell' );

 

$array3 = array ( '0' => 'gary' );

$array4 = array ( '0' => 'bakewell', [1] => 'gary' );

 

is to see if any of the items in array1  appear in array 2 but not an exact match. So in this case "gary" and "bakewell" are in both arrays so it will return true.

 

Or see if any items in $array3 are in $array4, so in this case true again because gary is in both

[seanlim]

maybe this?

 

if(count(array_diff($array1, $array2))==count($array1)){
// if none of the elements in $array1 are present in array2
return true;
}