[SOLVED] str_replace URL

[l0rdz3r0]

hello everyone i need some help in this i tried many ways i google it etc...

and yes i am new in this...

Here goes my headaches

 

$output1='<a href="http://www4.site.com/photo/a/user/img/pict/name1212.jpg" rel="nofollow">

<img src="http://www4.site.com/photo/a/user/img/pict/name1212.jpg" border="0" alt="name" /></a>';

 

 

i need to change /img/ to /thumb/ at <img src...

 

$links = str_replace('/img/', "/thumb/", $output1); this works but it changes the href too

what i need is some help to the function only change in <img src

somenting like this

$links = str_replace('/img/ |<img src', "/thumb/", $output1);

 

 

 

so the output will be

<a href="http://www4.site.com/photo/a/user/img/pict/name1212.jpg" rel="nofollow">

<img src="http://www4.site.com/photo/a/user/thumb/pict/name1212.jpg" border="0" alt="name" /></a>

[mrMarcus]

excuse me if i'm over-simplifying this, but couldn't you just do this:

 

$output1='<a href="http://www4.site.com/photo/a/user/img/pict/name1212.jpg" rel="nofollow">
<img src="http://www4.site.com/photo/a/user/thumb/pict/name1212.jpg" border="0" alt="name" /></a>';

 

why do you need to use str_replace() when you can just do it manually?  perhaps a little more insight to the use of this might help shed some better responses.

 

EDIT: if that won't do it for you, did you try this:

 

$output1 = str_replace ('<img src="http://www4.site.com/photo/a/user/img/', '<img src="http://www4.site.com/photo/a/user/thumb/', $output1);

 

pretty straight forward.

[GingerRobot]

mrMarcus, i'm assuming that those are example values for various parts of the URL.

 

To the OP: you'll need to use regular expressions. You can use the preg_replace function to do what you want.

[mrMarcus]

mrMarcus, i'm assuming that those are example values for various parts of the URL.

i'm not sure that's the case.

 

all that is needed is when there is an <img> tag present, have the directory point to /thumb/ and the <a> tag point to /img/.

 

now, call me crazy, but i would just hard-code it in if it's to be a constant.

 

for example, assume a setup like this:

<?php
$sql = mysql_query ("SELECT * FROM `table`");

while ($res = mysql_fetch_assoc ($sql))
{
$output1 = '<a href="http://www4.site.com/photo/a/user/img/pict/'.$img.'" rel="nofollow"><img src="http://www4.site.com/photo/a/user/thumb/pict/'.$img.'" border="0" alt="name" /></a>';

echo $output1;
}
?>

 

why the need to replace at all?  code-in one dir for thumbs, one for full-size.

 

i could be mistaken with how i interpreted the initial problem, and you're absolutely right, regex would take care of an issue like this .. but, is there really an issue?

 

[l0rdz3r0]

 

$output1 = str_replace ('<img src="http://www4.site.com/photo/a/user/img/', '<img src="http://www4.site.com/photo/a/user/thumb/', $output1);

 

pretty straight forward.

 

No i cant do that becouse a i get a list with multiple urls

 

 

for ex.

<a href="http://www4.site.com/photo/a/user/img/pict/name1212.jpg" rel="nofollow">

<img src="http://www4.site.com/photo/a/user/img/pict/name1212.jpg" border="0" alt="name" /></a>

<a href="http://www8.site.com/photo/a/user/img/pict/na433212.jpg" rel="nofollow">

<img src="http://www8.site.com/photo/a/user/img/pict/na433212.jpg" border="0" alt="name" /></a>

...

 

that why i need to get some that only change from img src...

 

[mrMarcus]

where are these link being drawn from?  an external source?  from a db?  do you have control over the path?

[MadTechie]

$output1 = preg_replace('%src="(.*?)/img%i', 'src="\1/thumb', $output1);

[l0rdz3r0]

thanks MadTechie

this is what i was looking

 

nice work thanks a lot

[MadTechie]

Welcome,

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