[SOLVED] MKTIME show months in order but starts with December not January with month =1

[jasonc]

for ($r=1; $r <= 12; $r++) {
echo(":" . date('F', mktime(0, 0, 0, $r, 0, 0)) .":");
}

 

produces

 

 

:December::January::February::March::April::May::June::July::August::September::October::November:

 

when it would seem it should be

 

:January::February::March::April::May::June::July::August::September::October::November::December:

 

in month/number order ?!

 

is there something wrong with this function or is there something wrong with my code ?

[Mchl]

Give it a year different from 0

[salathe]

There is nothing wrong with using year 0 (it equates to 2000). The problem is using day 0: a month starts with day 1 and 0 means the last day of the previous month. Just change the day parameter from 0 to 1.

[Mchl]

As usual I mixed up which goes first.

[jasonc]

thanks for that it works now i have taken out all the ending parts of the date that were not needed.

 

just used...  echo(":" . date('F', mktime(0, 0, 0, $r)) .":");

instead

 

thanks for your help

[salathe]

Be warned that by missing the $day parameter out, it will assume the current day. When it comes to the end of a month (anything after the 29th) you'll run into trouble since there is no 30th of some months (february will suffer even more). For example, if today was the 31st then the list of months would be :January::March::March::May::May::July::July::August::October::October::December::December:. Best just stick a 1 into the $day parameter.