rhale Posted November 3, 2009 Share Posted November 3, 2009 what i am trying to do is just get a value from sql and then put it into a variable, it prints out the right value but when i try to use it in the if statement below it just doesnt work and i get no error or anything $accesslevels = mysql_query("SELECT accesslevel FROM $tbl_name WHERE username='$myusername' and password ='$mypassword'"); $accesslevel = mysql_fetch_assoc($accesslevels); if($accesslevel=='2'){ echo $accesslevel['accesslevel']; } Link to comment https://forums.phpfreaks.com/topic/180054-solved-putting-data-from-sql-into-a-variable-then-using-it/ Share on other sites More sharing options...
Alex Posted November 3, 2009 Share Posted November 3, 2009 I think you're meaning to do: if($accesslevel['accesslevel']=='2') Link to comment https://forums.phpfreaks.com/topic/180054-solved-putting-data-from-sql-into-a-variable-then-using-it/#findComment-949891 Share on other sites More sharing options...
rhale Posted November 3, 2009 Author Share Posted November 3, 2009 tyvm that worked i am very new to php and sql and am still just learning if that seemed like a real easy mistake Link to comment https://forums.phpfreaks.com/topic/180054-solved-putting-data-from-sql-into-a-variable-then-using-it/#findComment-949893 Share on other sites More sharing options...
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