[SOLVED] help with infinite loop error

Jnerocorp · November 4, 2009

these are the 3 looped errors that come up in my error_log

[04-Nov-2009 15:33:22] PHP Warning:  fopen() expects at least 2 parameters, 1 given in /home/jnero/public_html/mydomainpagerank.com/search2/querygoogle.php on line 19
[04-Nov-2009 15:33:22] PHP Warning:  feof(): supplied argument is not a valid stream resource in /home/jnero/public_html/mydomainpagerank.com/search2/querygoogle.php on line 20
[04-Nov-2009 15:33:22] PHP Warning:  fread(): supplied argument is not a valid stream resource in /home/jnero/public_html/mydomainpagerank.com/search2/querygoogle.php on line 21

the error_log is here:

http://mydomainpagerank.com/search2/error_log

here is the pages that i have:

index.php:

<?php
include('config.php');
if(isset($_GET['q'])) {

$query = $_GET['q'];
$query = str_replace(" ","+",$query);
$murl = "http://mydomainpagerank.com/search2/index.php?searhquery=$query";
header('Location: ' . $murl);

}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Custom Google Search Page</title>
<meta name="description" content="Custom Google Search Page" />
<meta name="keywords" content="custom, google, search, page" />
<script type="text/javascript" src="includes/js.php"></script>
<link href="images/home.css" rel="stylesheet" type="text/css" />
<!--[if lte IE 6]>
    <link href="images/ie6.css" rel="stylesheet" type="text/css" />
<![endif]-->
<style type="text/css">

.searchresult
{
padding: 1.5em 0;
border-bottom: 1px solid #333;
}

.searchresult h3, .searchresult p
{
margin: 0;
}

.searchresult h3 a
{
font: italic 1em Georgia, serif;
color: #f30;
border-bottom: 1px solid #900;
text-decoration: none;
font-weight: bold;
font-size: 1em;
}

.searchresult .resultdesc b
{
color: #fff;
}

.searchresult .resulturl
{
color: #666;
font-size: .75em;
}

</style>
</head>
<body>
<div id="wrapper">
<div id="bg_t"> </div>
    <div id="bg_c">
    	<div id="logo">
		<a href="./index.php"><img src="./images/logo.png" border="0"></a>
        </div>
	<form method="get" action="querygoogle.php">    
        <div id="search">Search this site<input type="text" maxlength="255" title="Enter your keywords and click the search button" name="searchquery" /></label>

        </div>
        
        <div id="buttom">
            <input type="submit" value="Search" />
		</form>
        </div>
        </form>
	<br><br>
	                <?php
if(!empty($_SESSION['googleresults']))
{
echo $_SESSION['googleresults'];
unset($_SESSION['googleresults']);
}
?>
        <div id="newkey">
        	<div class="searchnew">
		<?php 
include('tag_cloud.php'); 

print tag_cloud();
?>
			<br clear="all" />                
            </div>
            <div class="searchnew_b">  </div>
        </div>
    </div>
    <div id="bg_b"> </div>
    <div id="footer">
    	Copyright © 2009 by <strong>Domain.com</strong>. All rights reserved - Script by: <a href="http://prophpdev.net/"><strong>ProPHPDev.net</strong></a>
    </div>
</div>
</body>
</html>

querygoogle.php:

<?php
session_start();

if(isset($_GET['searchquery'])) {

$searchquery = $_GET['searchquery'];
$searchquery = str_replace(" ","+",$searchquery);

// if you use an Mike Migurski's JSON library, include it like I did
require_once('JSON.phps');

// Here's the Google AJAX Search API url for curl. It uses Google Search's site:www.yourdomain.com syntax to search in a specific site. I used $_SERVER['HTTP_HOST'] to find my domain automatically. Change $_POST['searchquery'] to your posted search query

$handler = "'http://ajax.googleapis.com/ajax/services/search/web?rsz=large&v=1.0&q=$searchquery', 'rb'";
$url ="http://ajax.googleapis.com/ajax/services/search/web?rsz=large&v=1.0&q=$searchquery";

// use fopen and fread to pull Google's search results

$handle = fopen($handler);
while(!feof($handle)) {
$body .= fread($handle, 8192);
}

fclose($handle);

// now $body is the JSON encoded results. We need to decode them.

$json = new Services_JSON();
$json = $json->decode($body);

// now $json is an object of Google's search results and we need to iterate through it.

foreach($json->responseData->results as $searchresult)
{
if($searchresult->GsearchResultClass == 'GwebSearch')
{
$formattedresults .= '
<div class="searchresult">
<h3><a href="' . $searchresult->unescapedUrl . '">' . $searchresult->titleNoFormatting . '</a></h3>
<p class="resultdesc">' . $searchresult->content . '</p>
<p class="resulturl">' . $searchresult->visibleUrl . '</p>
</div>';
}
}

$query = $_GET['searchquery'];
$query = str_replace(" ","+",$query);
$murl = "http://mydomainpagerank.com/search2/index.php?search=$query";
$_SESSION['googleresults'] = $formattedresults;
header('Location: ' . $murl);
exit;
}
?>

.josh · November 4, 2009

did you actually read your error? It tells you what the problem is. fopen expects 2 parameters and you are only giving it one. Pretty self-explanatory. The other 2 errors are being caused because of fopen failing.

Jnerocorp · November 4, 2009

ok i changed the code around but still get this errror:

[04-Nov-2009 15:46:18] PHP Warning:  fread(): supplied argument is not a valid stream resource in /home/jnero/public_html/querygoogle.php on line 20

and the error just loops

this is the new code:

querygoogle.php:

<?php
session_start();

if(isset($_GET['searchquery'])) {

$searchquery = $_GET['searchquery'];
$searchquery = str_replace(" ","+",$searchquery);

// if you use an Mike Migurski's JSON library, include it like I did
require_once('JSON.phps');

// Here's the Google AJAX Search API url for curl. It uses Google Search's site:www.yourdomain.com syntax to search in a specific site. I used $_SERVER['HTTP_HOST'] to find my domain automatically. Change $_POST['searchquery'] to your posted search query

$url ="http://ajax.googleapis.com/ajax/services/search/web?rsz=large&v=1.0&q=$searchquery";

// use fopen and fread to pull Google's search results

$handle = fopen("$url", "rb");
while(!feof($handle)) {
$body .= fread("$handle", "8192");
}
fclose($handle);

// now $body is the JSON encoded results. We need to decode them.

$json = new Services_JSON();
$json = $json->decode($body);

// now $json is an object of Google's search results and we need to iterate through it.

foreach($json->responseData->results as $searchresult)
{
if($searchresult->GsearchResultClass == 'GwebSearch')
{
$formattedresults .= '
<div class="searchresult">
<h3><a href="' . $searchresult->unescapedUrl . '">' . $searchresult->titleNoFormatting . '</a></h3>
<p class="resultdesc">' . $searchresult->content . '</p>
<p class="resulturl">' . $searchresult->visibleUrl . '</p>
</div>';
}
}

$query = $_GET['searchquery'];
$query = str_replace(" ","+",$query);
$murl = "http://mydomainpagerank.com/search2/index.php?search=$query";
$_SESSION['googleresults'] = $formattedresults;
header('Location: ' . $murl);
exit;
}
?>

.josh · November 5, 2009

well it looks like you're putting all of the html into a single variable anyways, so instead of using that fopen and fread in a loop, just use file_get_contents

Jnerocorp · November 5, 2009

Im not exactly sure how i would replace my current code with file_get_conents()

Jnerocorp · November 5, 2009

can anyone help please?

-John

Jnerocorp · November 5, 2009

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[SOLVED] help with infinite loop error

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