PHP calendar - making 'today' appear in bold

[hawkontvn]

Hey. I learned PHP just recently, and I just managed to pull out making this calendar, but I wonder how I can make today's date appear in <b></b>.

 

Here's the code:

<?php

echo
"<style>.cal { float: right; }</style>";

// Get today's date
$date = time();

// Set day, month, and year in seperate variables
$day = date('d', $date);
$month = date('m', $date);
$year = date('Y', $date);

// Generate the first day of the month
$first_day = mktime(0,0,0,$month, 1, $year);

// Get the month name
$title = date('F', $first_day);

// Find out what day of the week the first day of the month falls on
$day_of_week = date('D', $first_day);

// Blank days before $day_of_week (0 if Sunday)
switch($day_of_week) 
{
case "Son": $blank = 0; break;
case "Man": $blank = 1; break;
case "Tir": $blank = 2; break;
case "Ons": $blank = 3; break;
case "Tor": $blank = 4; break;
case "Fre": $blank = 5; break;
case "Lor": $blank = 6; break;
}

// Determine number of days in current month
$days_in_month = cal_days_in_month(0, $month, $year);

// Building table heads
echo "<table border='1' width='194' class='cal'>";
echo "<tr><th colspan='7'> $title $year </th></tr>";
echo "<tr><td width='42'>S</td><td width='42'>M</td>
      <td width='42'>T</td><td width='42'>O</td><td width='42'>T</td>
      <td width='42'>F</td><td width='42'>L</td></tr>";
      
// Count the days in the week, up to 7
$day_count = 1;

echo "<tr>";
// Blank days first
while ($blank > 0) 
{
echo "<td></td>";
$blank = $blank-1;
$day_count++;
}

// Set the first day of the month to 1
$day_num = 1;

// Count all the days in the month
while ($day_num <= $days_in_month) 
{
echo "<td> $day_num </td>";
$day_num++;
$day_count++;

// New row for every week
if ($day_count > 7)
{
echo "</tr><tr>";
$day_count = 1;
}
}

// End of month, blank days (if needed)
while ($day_count > 1 && $day_count <= 7)
{
echo "<td> </td>";
$day_count++;
}

echo "<tr></table>";

 

Thanks

[Mchl]

Like this for example

 

// Count all the days in the month
while ($day_num <= $days_in_month) 
{
if ($day != $day_num) {
  echo "<td> $day_num </td>";
} else {
  echo "<td><b> $day_num </b></td>";
}
$day_num++;
$day_count++;