[SOLVED] Testing if exists in ARRAY

[brmcdani]

I recently wrote a PHP script to add to my registration page that allows for human verification by pulling random strings out of an array.  I am having trouble making my if statement work to where it checks the array before approving the user's registration.  Here is what I have so far:

 

$verification = protect($_POST['verification']);

if($verification != $rand){
        	echo "Sorry but the number verification you entered was not correct";
        }

$rand = array("asfd7", "ghdg3", "kfdr6", "sdas3", "hdsa6", "gdsd9", "ijko5");
$keys = array_rand($rand, 1);
echo "Verification letters:  ";
echo $rand[$keys];

 

Can someone please point me in the right direction?

 

Thanks

[darkvengance]

You should check out the in_array() function...but here is what you are trying to do...I think:

 

 

 

$verification = protect($_POST['verification']);

$rand = array("asfd7", "ghdg3", "kfdr6", "sdas3", "hdsa6", "gdsd9", "ijko5");

if(!in_array($verification,$rand)){
       	echo "Sorry but the number verification you entered was not correct";
        }
$keys = array_rand($rand, 1);
echo "Verification letters:  ";
echo $rand[$keys];

[brmcdani]

Ok that worked great, thanks!  I was in the middle of looking at that in the manual when I got your post.  What would I do if I want to end the registration if it is not in the array?  Even if the verification is wrong it still registers the user?  Any ideas?

[brmcdani]

Nevermind got it!