terrymechan Posted April 29, 2004 Share Posted April 29, 2004 I have a code problem I havea list/menu box in a form, which will be updated on submission The list is a list of countries from a My Sql Table. I wish to pre-enter the record which already exists, which I can do from identifying the Unique record ID. However, I then want the drop down box reveal all the countries listed in that table For some reason, I can either populate the drop down list with this coding <select name="Ecom_ShipTo_Postal_CountryCode" > <?php while(!$countrylist->EOF){ ?> <option value="<?php echo $countrylist->Fields('COUNTRY')?>"><?php echo $countrylist->Fields('COUNTRY')?></option> <?php $countrylist->MoveNext(); } $countrylist->MoveFirst(); ?> or insert the existing choice of the user, by adding this code. <select name="Ecom_ShipTo_Postal_CountryCode" title="<?php echo $existingrecord->Fields('Country'); ?>" > <?php while(!$countrylist->EOF){ ?> <option value="<?php echo $countrylist->Fields('COUNTRY')?>"><?php echo $countrylist->Fields('COUNTRY')?></option> <?php $countrylist->MoveNext(); } $countrylist->MoveFirst(); ?> </select> What I need is code which will display the existing entry, AND allow the drop down list box to display the countries from the MYsql table Quote Link to comment Share on other sites More sharing options...
morpheus.100 Posted April 30, 2004 Share Posted April 30, 2004 Add a static entry to the dynamic menu and and use the selected tag to make it initially selected Quote Link to comment Share on other sites More sharing options...
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