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Unknown php error Oo

Tuck

By Tuck
in PHP Coding Help

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Tuck Member

Tuck

Posted
Posted

this is my code i have no idea why it errors :(

 

<?php
   if ((isset($_GET['U'])) && (isset($_GET['P'])) && (isset($_GET['ID'])) && (Logins($_GET['U'],$_GET['P']))) {
      echo = "1";
      $referer = $_SERVER['HTTP_REFERER'];
      if (isset($referer)) {
         $con = mysql_connect('link', 'db', 'pw');
         if (!$con) { die('Error: ' . mysql_error()); }
         mysql_select_db('db', $con);
         mysql_query("DELETE FROM `Bump` WHERE `ID`='" . $_GET['ID'] . "'");
         mysql_close($con);
         header("Location: " . $referer);
      } else {
         die("<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r<HTML><HEAD>\r<TITLE>403 Forbidden</TITLE>\r</HEAD><BODY>\r<H1>Forbidden</H1>\rYou don't have permission to access \rthis server.<P>\r</BODY></HTML>");
      }
   } else {
      die("<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r<HTML><HEAD>\r<TITLE>403 Forbidden</TITLE>\r</HEAD><BODY>\r<H1>Forbidden</H1>\rYou don't have permission to access \rthis server.<P>\r</BODY></HTML>");
   }
   function Logins($Username,$Password) {
      if (strtoupper($Username) == strtoupper("js")) {
         if (strtoupper($Password) == strtoupper("uhg")) {
            return 1;
         }
      }
      if (strtoupper($Username) == strtoupper("blah")) {
         if (strtoupper($Password) == strtoupper("bahf")) {
            return 1;
         }
      }
      return 0;
   }
?>

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rajivgonsalves Newbie

rajivgonsalves

Posted
Posted

you have used way too many braces (Causes lots of confusion) also you had a syntax error here is some code which should work

 

<?php
   if (isset($_GET['U']) && isset($_GET['P']) && isset($_GET['ID']) && Logins($_GET['U'],$_GET['P'])) {
      $referer = $_SERVER['HTTP_REFERER'];
      
      if (isset($referer)) {
         $con = mysql_connect('link', 'db', 'pw');
         if (!$con) { die('Error: ' . mysql_error()); }
         mysql_select_db('db[b][/b]', $con);
         mysql_query("DELETE FROM `Bump` WHERE `ID`='" . $_GET['ID'] . "'");
         mysql_close($con);
         header("Location: " . $referer);
      } 
      else {
         die("<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r<HTML><HEAD>\r<TITLE>403 Forbidden</TITLE>\r</HEAD><BODY>\r<H1>Forbidden</H1>\rYou don't have permission to access \rthis server.<P>\r</BODY></HTML>");
      }
   } 
   else {
      die("<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r<HTML><HEAD>\r<TITLE>403 Forbidden</TITLE>\r</HEAD><BODY>\r<H1>Forbidden</H1>\rYou don't have permission to access \rthis server.<P>\r</BODY></HTML>");
   }
   
   function Logins($Username,$Password) {
      if (strtoupper($Username) == strtoupper("js")) {
         if (strtoupper($Password) == strtoupper("uhg")) {
            return 1;
         }
      }
      if (strtoupper($Username) == strtoupper("blah")) {
         if (strtoupper($Password) == strtoupper("bahf")) {
            return 1;
         }
      }
      return 0;
   }
?>

 

 

 

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Tuck Member

Tuck

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  • Author
Posted

It would help if we had the error message. This is the equivalent of..."It don't work"

 

white screen no html source happy?

 

you have used way too many braces (Causes lots of confusion) also you had a syntax error here is some code which should work

 

<?php
   if (isset($_GET['U']) && isset($_GET['P']) && isset($_GET['ID']) && Logins($_GET['U'],$_GET['P'])) {
      $referer = $_SERVER['HTTP_REFERER'];
      
      if (isset($referer)) {
         $con = mysql_connect('link', 'db', 'pw');
         if (!$con) { die('Error: ' . mysql_error()); }
         mysql_select_db('db[b][/b]', $con);
         mysql_query("DELETE FROM `Bump` WHERE `ID`='" . $_GET['ID'] . "'");
         mysql_close($con);
         header("Location: " . $referer);
      } 
      else {
         die("<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r<HTML><HEAD>\r<TITLE>403 Forbidden</TITLE>\r</HEAD><BODY>\r<H1>Forbidden</H1>\rYou don't have permission to access \rthis server.<P>\r</BODY></HTML>");
      }
   } 
   else {
      die("<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r<HTML><HEAD>\r<TITLE>403 Forbidden</TITLE>\r</HEAD><BODY>\r<H1>Forbidden</H1>\rYou don't have permission to access \rthis server.<P>\r</BODY></HTML>");
   }
   
   function Logins($Username,$Password) {
      if (strtoupper($Username) == strtoupper("js")) {
         if (strtoupper($Password) == strtoupper("uhg")) {
            return 1;
         }
      }
      if (strtoupper($Username) == strtoupper("blah")) {
         if (strtoupper($Password) == strtoupper("bahf")) {
            return 1;
         }
      }
      return 0;
   }
?>

 

could you atlest tell me what syntax error and stuff >_>

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Tuck Member

Tuck

Posted
  • Author
Posted

 

white screen no html source happy?

 

 

And you actually expect a reply?  :wtf:

 

if i knew how to debug php i would but php sucks so much if 1 error it all errors.. and dosent tell anything about it >_>

 

<?php
   if (isset($_GET['U']) && isset($_GET['P']) && isset($_GET['ID']) && Logins($_GET['U'],$_GET['P'])) {
      echo = "<html></html>";
      $referer = $_SERVER['HTTP_REFERER'];
      if (isset($referer)) {
         $con = mysql_connect('', 'virus_clan_net', '');
         if (!$con) { die('Error: ' . mysql_error()); }
         mysql_select_db('virus_clan_net', $con);
         mysql_query("DELETE FROM `Bump` WHERE `ID`='" . $_GET['ID'] . "'");
         mysql_close($con);
         header("Location: " . $referer);
      } else {
         die("<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r<HTML><HEAD>\r<TITLE>403 Forbidden</TITLE>\r</HEAD><BODY>\r<H1>Forbidden</H1>\rYou don't have permission to access \rthis server.<P>\r</BODY></HTML>");
      }
   } else {
      die("<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r<HTML><HEAD>\r<TITLE>403 Forbidden</TITLE>\r</HEAD><BODY>\r<H1>Forbidden</H1>\rYou don't have permission to access \rthis server.<P>\r</BODY></HTML>");
   }
   function Logins($Username,$Password) {
      if (strtoupper($Username) == strtoupper("Tuck")) {
         if (strtoupper($Password) == strtoupper("")) {
            return 1;
         }
      }
      if (strtoupper($Username) == strtoupper("Jonny")) {
         if (strtoupper($Password) == strtoupper("")) {
            return 1;
         }
      }
      return 0;
   }
?>

 

the code code dosent work still :/

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j0n Newbie

j0n

Posted
Posted

if i knew how to debug php i would but php sucks so much if 1 error it all errors.. and dosent tell anything about it >_>

 

at the top of your script, try this:

 

ini_set('display_errors', 1);

 

Don't be so rude to people trying to help you, or you'll find your threads quickly go unanswered.

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Tuck Member

Tuck

Posted
  • Author
Posted

if i knew how to debug php i would but php sucks so much if 1 error it all errors.. and dosent tell anything about it >_>

 

at the top of your script, try this:

 

ini_set('display_errors', 1);

 

Don't be so rude to people trying to help you, or you'll find your threads quickly go unanswered.

 

i'm mad at php not any person >_> but thanks will try

 

@thanks with the echo answer btw

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