tool38 Posted November 20, 2009 Share Posted November 20, 2009 Hello Thanks for any help any one can give Im very new to PHP.. I need to pull data for clients that share 2 diff services into one table. mysql_select_db($database_pull, $pull); $query_Recordset1 = "SELECT * FROM RR_services WHERE USER_ID='XXXXX' and ( GAME_ID = 'RR6261678786234' or GAME_ID = 'RR4148833526812' )"; $Recordset1 = mysql_query($query_Recordset1, $pull) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); ?> This does what i need but i have to define the USER_ID i would like it to search all users and just display results of those that have both services.. Thanks Again, Link to comment https://forums.phpfreaks.com/topic/182345-solved-filtering-tables/ Share on other sites More sharing options...
MatthewJ Posted November 21, 2009 Share Posted November 21, 2009 <?php mysql_select_db($database_pull, $pull); $query_Recordset1 = "SELECT * FROM RR_services WHERE GAME_ID = 'RR6261678786234' or GAME_ID = 'RR4148833526812'"; $Recordset1 = mysql_query($query_Recordset1, $pull) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); ?> Link to comment https://forums.phpfreaks.com/topic/182345-solved-filtering-tables/#findComment-962284 Share on other sites More sharing options...
tool38 Posted November 21, 2009 Author Share Posted November 21, 2009 Thank you for the response . I started over and found a variable that both services shared so no need to filter.. Link to comment https://forums.phpfreaks.com/topic/182345-solved-filtering-tables/#findComment-962402 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.