Load file in PHP

Graxeon · November 28, 2009

I have 2 files. The first is a PHP generated XML file that's dependent by 2 inputs. The second is a PHP file that grabs the content of the XML file.

So I have this:

site.com/xml.php?p=RAINBOW&z=SOCCER

<playlist version="1">

<trackList>

<track>
<title>SOCCER - RAINBOW</title>
<location>http://www.site.com/soccer-rainbow.m4v</location>
<duration>23:27</duration>
<info>http://www.site.com/info.php?video=RAINBOW&title=SOCCER</info>
<meta rel="type">m4v</meta>
<image>images.php?title=SOCCER&video=RAINBOW</image>
</track>

<track>
<title>SOCCER</title>
<location/>
<meta rel="type"/>
</track>
</trackList>
</playlist>

I want to grab the contents of the "location" tags.

So, I have this now:

media.php?p=RAINBOW&z=SOCCER

$title = $_GET['p'];
$video = $_GET['z']; 

$myXML = 'www.site.com/xml.php?p=' .$title. '&z='.$video;

$sxml = simplexml_load_string($myXML);
list($node) = $sxml->xpath('/playlist/trackList/track/location');
header("Location: $node");

But I get the error "Fatal error: Call to a member function xpath() on a non-object on line 9".

What variables did I mess up? Can someone help me fix it, please?

Alex · November 28, 2009

use simplexml_load_file, not simplexml_load_string().

Graxeon · November 28, 2009

I just get a blank page with that change

Edit:

Even when I make $myXML = 'site.com/xml.xml' where "xml.xml" is the full XML file, I get this error:

Fatal error: Call to a member function xpath() on a non-object on line 7

Alex · November 28, 2009

You should include http:// in the URL.

Graxeon · November 28, 2009

The error is with the full link in place. So it's not a URL problem.

Alex · November 28, 2009

Is this what you're doing?:

$myXML = 'http://www.site.com/xml.php?p=' .$title. '&z='.$video;

$sxml = simplexml_load_file($myXML);

Graxeon · November 28, 2009

Yes, I am. However...this gives a blank page:

<?php

$title = $_GET['p'];
$video = $_GET['z'];

$myXML = 'http://www.site.com/media.php?p=' .$title. '&z='.$video;

$sxml = simplexml_load_file($myXML);
list($node) = $sxml->xpath('/playlist/trackList/track/location');
header("Location: $node");

?>

So, I wanted to test to see if I'm even linking correctly and did this:

<?php

$myXML = 'http://www.site.com/xml.xml';

$sxml = simplexml_load_file($myXML);
list($node) = $sxml->xpath('/playlist/trackList/track/location');
header("Location: $node");

?>

And that gave me the fatal error.

So, even when I link it directly to an already generated XML file, I get an error. Idk if that helps at all, though.

THIS, however, works:

<?php
$myXML ='<playlist version="1">

<trackList>

<track>
<title>SOCCER - RAINBOW</title>
<location>http://www.site.com/soccer-rainbow.m4v</location>
<duration>23:27</duration>
<info>http://www.site.com/info.php?video=RAINBOW&title=SOCCER</info>
<meta rel="type">m4v</meta>
<image>images.php?title=SOCCER&video=RAINBOW</image>
</track>

<track>
<title>SOCCER</title>
<location/>
<meta rel="type"/>
</track>
</trackList>
</playlist>';

$sxml = simplexml_load_string($myXML);
list($node) = $sxml->xpath('/playlist/trackList/track/location');
header("Location: $node");
?>

Why doesn't it work when I don't put the XML file in the $myXML var and just link to it?

Alex · November 28, 2009

Looks like you can't grab remote files (fopen_wrappers is probably disabled). You might want to try cURL to obtain the remote xml file.

Graxeon · November 28, 2009

Huh?

Alex · November 28, 2009

Grab the remote xml file using cURL as a string and then pass it into simplexml_load_string().

Graxeon · November 29, 2009

I don't really understand cURL. I'm not too great with PHP. Can you help me with it, please?

Graxeon · November 29, 2009

Are you there Alex?

Alex · November 29, 2009

Here's an example:

$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, 'WEBSITE URL HERE');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$myXML = curl_exec ($curl);
curl_close($curl);

// .. The rest of your code

Graxeon · November 29, 2009

Like this? Cause this gives a blank page:

<?php

$title = $_GET['p'];
$video = $_GET['z'];

$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, 'http://www.site.com/media.php?p=' .$title. '&z='.$video);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$myXML = curl_exec ($curl);
curl_close($curl);

$sxml = simplexml_load_file($myXML);
list($node) = $sxml->xpath('/playlist/trackList/track/location');
header("Location: $node");

?>

Or which code are you talking about?

Alex · November 29, 2009

Yes, except for use simplexml_load_string() inside of simplexml_load_file() now that you should have the contents of the XML file in $myXML.

Graxeon · November 29, 2009

Nope, still get a blank page.

Is there a simpler way of getting the content within the "location" tags in the XML file?:

http://www.site.com/xml.php?p=RAINBOW&z=SOCCER

<playlist version="1">

<trackList>

<track>
<title>SOCCER - RAINBOW</title>
<location>http://www.site.com/soccer-rainbow.m4v</location>
<duration>23:27</duration>
<info>http://www.site.com/info.php?video=RAINBOW&title=SOCCER</info>
<meta rel="type">m4v</meta>
<image>images.php?title=SOCCER&video=RAINBOW</image>
</track>

<track>
<title>SOCCER</title>
<location/>
<meta rel="type"/>
</track>
</trackList>
</playlist>

Alex · November 29, 2009

Can you post the actual link to the website so I can try this myself?

Graxeon · November 29, 2009

I can't give you the actual website without confirmation from the owner.

However, that XML file is the same exact copy. How it's generated is complex, however the final output is that. So, the URL that I'm giving is the basic setup that leads to that XML content.

So it's the same thing. I can upload a plain XML file with that same content for you, but the "p=" and "z=" won't be part of the execution (though ofc that can be added later). Here's a test XML file with the same thing: http://fr33.ulmb.com/gr/xml.xml

Sorry for taking up your time, I just really need to finish this.

EDIT: I have to head out to work. If you want me to answer anything just leave a post, I'll be back in about 10 hours. Again, thatnks for your time!

Alex · November 29, 2009

Uploading the xml file to a remote local myself and testing this it worked fine:

$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, 'http://website.com/somefile.xml');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$myXML = curl_exec ($curl);
curl_close($curl);

$sxml = simplexml_load_string($myXML);
list($node) = $sxml->xpath('/playlist/trackList/track/location');
header("Location: $node");

I suggest you put error_reporting(E_ALL); at the top of your page and post back any errors.

Graxeon · November 29, 2009

Tried that, got this:

Fatal error: Call to a member function xpath() on a non-object on line 10

Did the same thing as you (uploaded it remotely with NO "p=" and "z=" inputs).

How is it a non-object?

Alright, I'm off before I'm late.

Alex · November 29, 2009

You're obviously having a problem getting the contents of the file. Check to see if $myXML contains the contents of the file you expect it does.

Graxeon · November 29, 2009

Here are my files:

http://fr33.ulmb.com/gr/grzid6.php

<?php

$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, 'http://fr33.ulmb.com/gr/xml.xml');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$myXML = curl_exec ($curl);
curl_close($curl);

$sxml = simplexml_load_string($myXML);
list($node) = $sxml->xpath('/playlist/trackList/track/location');
header("Location: $node");

?>

http://fr33.ulmb.com/gr/xml.xml

<playlist version="1">

<trackList>

<track>
<title>SOCCER - RAINBOW</title>
<location>http://www.site.com/soccer-rainbow.m4v</location>
<duration>23:27</duration>
<info>http://www.site.com/info.php?video=RAINBOW&title=SOCCER</info>
<meta rel="type">m4v</meta>
<image>images.php?title=SOCCER&video=RAINBOW</image>

</track>

<track>
<title>SOCCER</title>
<location/>
<meta rel="type"/>
</track>
</trackList>
</playlist>

Did I mess something up?

Alex · November 29, 2009

That won't work because http://fr33.ulmb.com/gr/xml.xml prompts you for a 60 second wait before downloading the file, so you'll be getting the contents of that page, not the actual xml file.

Graxeon · November 29, 2009

Is there a way around that?

But either way, it's the same content, isn't it?

Alex · November 29, 2009

No, it's not the same content, completely different. If you try to get the contents of that page you get:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=us-ascii"> 
<title>Download xml.xml</title> 
<script type="text/javascript" language="JavaScript"><!--
function docountdown(){
s_div = document.getElementById("dldiv");
count = count - 1;

if (count > 0){
s_div.innerHTML = "Your request to download xml.xml is being processed.<"+"p>Please Wait... ("+count+" seconds remaining)<"+"/p>";
setTimeout("docountdown();", 1000);
} else {
s_div.innerHTML = "Your file is ready for download.<"+"p><"+"a href=\"/gr/xml.xml?\">Click here to Download File<"+"/a><"+"/p>";
}
}

var count = 60;
window.onload = docountdown;
--></script> 
</head> 
<body> 
<div align="center"> 
<script type="text/javascript"><!--
google_ad_client = "pub-2927823587298693";
google_alternate_color = "FFFFFF";
google_ad_width = 468;
google_ad_height = 60;
google_ad_format = "468x60_as";
google_ad_channel ="";
google_color_border = "336699";
google_color_bg = "FFFFFF";
google_color_link = "0000FF";
google_color_url = "008000";
google_color_text = "000000";
//--></script> 
<script type="text/javascript"

  src="http://pagead2.googlesyndication.com/pagead/show_ads.js"> 
</script> 
<br /><br /> 
<table border="0" width="500"> 
	<tr> 
		<td> 
			<fieldset style="padding: 2"> 
			<legend>Download xml.xml</legend> 
			<br /> 
			<div id="dldiv"> 
			Your request to download xml.xml is being processed.<p>Please Wait...</p> 
			</div> 
			<br /> 
			</fieldset> 
		<p> </td> 
	</tr> 
</table> 
<script type="text/javascript"><!--
google_ad_client = "pub-2927823587298693";
google_alternate_color = "FFFFFF";
google_ad_width = 468;
google_ad_height = 60;
google_ad_format = "468x60_as";
google_ad_channel ="";
google_color_border = "336699";
google_color_bg = "FFFFFF";
google_color_link = "0000FF";
google_color_url = "008000";
google_color_text = "000000";
//--></script> 
<script type="text/javascript"

  src="http://pagead2.googlesyndication.com/pagead/show_ads.js"> 
</script> 
</div> 
</body> 
</html>

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Load file in PHP

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