ROCKINDANO Posted November 30, 2009 Share Posted November 30, 2009 Hey all i have a problem, i have a page that displays a list of records (files) for this year but i want to display two types of files. these files that i am trying to display have a a small version of the file and a large version of the file. i need to display both ver. from two db tables that are hold all the information from both files. this is what i have: <?php if(!($db = @ mysql_connect('localhost', 'un', 'pass'))) { print "Error: Could not connect to our database sorry for any inconvience.<br /> Please try at a later time."; } //select which database you want to edit mysql_select_db("db_name"); $agenda_id=$_GET[agenda_id]; print "<center><table width=\"100%\" border=\"0\" cellpadding=\"1\" cellspacing=\"0\" style=\"border: 0px solid #2c4876\"><tr bgcolor='#0000ff' style='font-weight: bold; color: #ffffff;'><td width='20%' align='center'>Meeting Date</td><td align='center' width='20%'>Agenda Notice</td><td align='center' width='19%'>Agenda Packet</td>"; $query="SELECT * FROM ccagenda ORDER BY agenda_id DESC"; $result=mysql_query($query); while ($r=mysql_fetch_array($result)) { $agenda_id=$r['agenda_id']; $adate=$r['adate']; $file=$r['file']; print "<tr><td colspan=\"3\">"; print "<table width=\"100%\" border=\"0\" cellpadding=\"1\" cellspacing=\"2\" bgcolor=\"#d2d6db\">"; print "<tr>"; print "<td width=\"20%\" align=\"left\" style=\"color:#3949f9\">" .strtoupper($adate). "</td>"; print "<td align=\"right\" width=\"20%\"><a href='pdfs/citysect/{$file}' target='_blank'>Agenda</a> <img src=\"images/pdfimage.png\" title=\"\" border=\"0\" /></td>"; $query2 = "SELECT * FROM packets"; $result2 = mysql_query($query2); while ($r = mysql_fetch_array($result2)) { $agenda_id = $r['agenda_id']; $file2 = $r['file']; $adate=$r['adate']; if($file2 == $file) { print "<td width='19%' style=\"text-align: right\"><a href='pdfs/citysect/packets/{$file}' target='_blank'>Full Packet </a><img src=\"images/pdfimage.png\" title=\"\" border=\"0\" /></td><td> </td>"; } else if($file2 != $file) print "<td width='19%' align='right'>No Packets</td>"; } print "</tr>"; print "</table>"; print "</td></tr>"; } print "</table></center>"; ?> can someone help me? thank you in advance Link to comment https://forums.phpfreaks.com/topic/183457-displaying-records-from-db/ Share on other sites More sharing options...
ROCKINDANO Posted November 30, 2009 Author Share Posted November 30, 2009 I forgot to mention. right now if i add to the large table it adds a new column to the page. i want to keep it from doing that. Link to comment https://forums.phpfreaks.com/topic/183457-displaying-records-from-db/#findComment-968381 Share on other sites More sharing options...
ROCKINDANO Posted November 30, 2009 Author Share Posted November 30, 2009 can someone tell me why why this piece of code is doing this? <?php $query="SELECT * FROM ccagenda ORDER BY agenda_id DESC"; $result=mysql_query($query); while ($r=mysql_fetch_array($result)) { $agenda_id=$r['agenda_id']; $adate=$r['adate']; $file=$r['file']; print "<tr><td colspan=\"3\">"; print "<table width=\"100%\" border=\"1\" cellpadding=\"1\" cellspacing=\"2\" bgcolor=\"#d2d6db\">"; print "<tr>"; print "<td width=\"20%\" align=\"left\" style=\"color:#3949f9\">" .strtoupper($adate). "</td>"; print "<td align=\"right\" width=\"20%\"><a href='pdfs/citysect/{$file}' target='_blank'>Agenda</a> <img src=\"images/pdfimage.png\" title=\"\" border=\"0\" /></td>"; $query2 = "SELECT * FROM packets where file = '{$file}'"; $result2 = mysql_query($query2); while ($r = mysql_fetch_array($result2)) { $agenda_id = $r['agenda_id']; $file2 = $r['file']; $adate=$r['adate']; // if($file2 == $file) print "<td width='19%' style=\"text-align: right\"><a href='pdfs/citysect/packets/{$file}' target='_blank'>Full Packet </a><img src=\"images/pdfimage.png\" title=\"\" border=\"0\" /></td>"; //IT IS NOT GOING INTO THIS IF STATEMENT. AND DOESN'T PRINT THE if($file2 != $file) print "<td width='19%' align='right'>No Packet</td>"; } print "</tr>"; print "</table>"; print "</td></tr>"; } print "</table></center>"; ?> Link to comment https://forums.phpfreaks.com/topic/183457-displaying-records-from-db/#findComment-968425 Share on other sites More sharing options...
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