aashcool198 Posted December 8, 2009 Share Posted December 8, 2009 Hi, i am trying to send data from database into an excel sheet. i have the but it creates a new excel sheet. I want my old template of excel sheet. Is there any way to copy the old template into the new excel file? <? // Connect database. mysql_connect("localhost","root",""); mysql_select_db("indiainterns"); // Get data records from table. $result=mysql_query("select * from name_list order by id asc"); // Functions for export to excel. function xlsBOF() { echo pack("ssssss", 0x809, 0x8, 0x0, 0x10, 0x0, 0x0); return; } function xlsEOF() { echo pack("ss", 0x0A, 0x00); return; } function xlsWriteNumber($Row, $Col, $Value) { echo pack("sssss", 0x203, 14, $Row, $Col, 0x0); echo pack("d", $Value); return; } function xlsWriteLabel($Row, $Col, $Value ) { $L = strlen($Value); echo pack("ssssss", 0x204, 8 + $L, $Row, $Col, 0x0, $L); echo $Value; return; } header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Type: application/force-download"); header("Content-Type: application/octet-stream"); header("Content-Type: application/download");; header("Content-Disposition: attachment;filename=india.xls "); header("Content-Transfer-Encoding: binary "); xlsBOF(); /* Make a top line on your excel sheet at line 1 (starting at 0). The first number is the row number and the second number is the column, both are start at '0' */ /* xlsWriteLabel(0,0,"List of car company."); // Make column labels. (at line 3) xlsWriteLabel(2,0,"No."); xlsWriteLabel(2,1,"Company"); */ $xlsRow = 12; // Put data records from mysql by while loop. while($row=mysql_fetch_array($result)){ xlsWriteNumber($xlsRow,0,$row['id']); xlsWriteLabel($xlsRow,1,$row['name']); $xlsRow++; } xlsEOF(); exit(); Quote Link to comment https://forums.phpfreaks.com/topic/184358-sending-mysql-data-to-excel-sheet/ Share on other sites More sharing options...
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