jeff5656 Posted December 8, 2009 Share Posted December 8, 2009 I have this error, but an't seem to find where it is: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' sex, comments, init_date, conf_date, signoff_status) VALUES('','bobby','', '' at line 1 if ($_POST['conf_date']==''){ $conf_date ='2030-01-01'; } else { $conf_date = date("Y-m-d", strtotime($_POST['conf_date'])); } $tx = mysql_real_escape_string($_POST['tx']); $primpulm = mysql_real_escape_string($_POST['primpulm']); $rheum = mysql_real_escape_string($_POST['rheum']); $dx = mysql_real_escape_string($_POST['dx']); $bx = mysql_real_escape_string($_POST['bx']); $bx_date = date("Y-m-d", strtotime($_POST['bx_date'])); $comments = mysql_real_escape_string($_POST['comments']); //add to main table $query = "INSERT INTO ild (id_incr, lname, fname, mrn, physician, primpulm, rheum, dx, bx, bx_date, $datedump, sex, comments, init_date, conf_date, signoff_status) VALUES('$id_incr','$lname','$fname', '$mrn', '$physician','$primpulm','$rheum', '$dx','$bx', '$bx_date','$dob','$sex', '$comments', '$init_date', '$conf_date', 'a')"; mysql_query($query) or die(mysql_error()); $pt_id = mysql_insert_id(); When I echo $query, it does indeed echo back all the values, before giving me the above error. Quote Link to comment Share on other sites More sharing options...
jeff5656 Posted December 8, 2009 Author Share Posted December 8, 2009 never mind i had an undeclared variable in the query. Quote Link to comment Share on other sites More sharing options...
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