preg_replace trouble

[newbtophp]

Hmm im having abit of trouble, how would i replace:

 

;echo '
';

(contains a new line after opening quote).

 

with:

 

?>
<?php

 

 

Example:

 

<?php
include("../config.php");
;echo '
';
$variable = "test";
echo $variable;
?>

 

Would turn into:

 

<?php
include("../config.php");
?>
<?php
$variable = "test";
echo $variable;
?>

 

:-\

[newbtophp]

My try - altough no luck:

$variable = preg_replace("#;echo '[\s]';#", "?>\r\n<?php", $variable);

[salathe]

Do you really need a regular expression?

 

$variable = str_replace(";echo '\n';", "?>\n<?php", $variable);

 

(If the string contains \r\n style newlines, use that instead of just \n.)

[newbtophp]

Do you really need a regular expression?

 

$variable = str_replace(";echo '\n';", "?>\n<?php", $variable);

 

(If the string contains \r\n style newlines, use that instead of just \n.)

 

Thanks mate!!

 

 

works perfect.!