Wayniac Posted December 8, 2009 Share Posted December 8, 2009 I can't seem to get the image upload and entry text (title, age, testimonial) to work the same time and on the same id. When I connect to the database through include("config.php"); , it works for the entry text, but the image won't show up. It will however add an id in the database for both entry text and image by adding 2 entries. One for the image which is not uploaded, and the other for the entry text which is uploaded. The oposite affect of this happens if I comment out the include("config.php"); , and connect to the database directly by using $errmsg = ""; //if (! @mysql_connect("localhost","root","")) { // $errmsg = "Cannot connect to database"; // } @mysql_select_db("album"); I would REALLY appreciate any help offered. <?php //error_reporting(0); include("config.php"); // Connect to database /*$errmsg = ""; //if (! @mysql_connect("localhost","root","")) { // $errmsg = "Cannot connect to database"; // } @mysql_select_db("album"); */ // Insert any new image into database if ($_REQUEST[completed] == 1) { // Need to add - check for large upload. Otherwise the code // will just duplicate old file ;-) // ALSO - note that latest.img must be public write and in a // live appliaction should be in another (safe!) directory. move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { mysql_query ("insert into album (title, imgdata) values (\"". $_REQUEST[whatsit]. "\", \"". $image. "\")"); } else { $errmsg = "Too large!"; } } // Find out about latest image $gotten = @mysql_query("select * from album order by albumid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../upload/example_1.jpg","rb"); $bytes = fread($instr,filesize("../upload/example_1.jpg")); } // If this is the image request, send out the image if ($_REQUEST[gim] == 1) { header("Content-type: image/jpeg"); print $bytes; exit (); } if(isset($_POST['submit'])) {//begin of if($submit). // Set global variables to easier names // and pervent sql injection and apostrophe to break the db. $title = mysql_real_escape_string($_POST['title']); $age = mysql_real_escape_string($_POST['age']); $testimonial = mysql_real_escape_string($_POST['testimonial']); //check if (title) field is empty then print error message. if(!$title){ //this means If the title is really empty. echo "Error: Entry title is a required field. Please fill it."; exit(); //exit the script and don't do anything else. }// end of if //run the query which adds the data gathered from the form into the database $result = mysql_query("INSERT INTO album (title, dtime, age, testimonial) VALUES ('$title',NOW(),'$age','$testimonial')",$connect); //print success message. echo "<b>Thank you! News added Successfully!<br>You'll be redirected to Home Page after (4) Seconds"; echo "<meta http-equiv=Refresh content=4;url=index.php>"; }//end of if($submit). // If the form has not been submitted, display it! else {//begin of else ?> <br> <h3>::Add News</h3> <font color=red> <?= $errmsg ?> </font> <center> <img src=?gim=1 width=500><br> <b> <?= $title ?> </center> <hr> <h2>Please upload a new picture and title</h2> <form action="<?php $_SERVER['PHP_SELF'] ?>" method="post" enctype="multipart/form-data" name="" id=""> <input type="hidden" name="MAX_FILE_SIZE" value="15000000"> Please choose an image to upload: <input type="file" name="imagefile"> <br> <!--Please enter the title of that picture: <input name="whatsit"><br>--> then: <br> <hr> <input type="hidden" name="completed" value="1"> <p> Title: <input name="title" size="40" maxlength="255"> <br> Age: <textarea name="age" rows="7" cols="30"></textarea> <br> Testimonial: <textarea name="testimonial" rows="7" cols="30"></textarea> <br> <input type="submit" name="submit" value="Add News"> </form> <?php }//end of else ?> Link to comment https://forums.phpfreaks.com/topic/184433-image-text-upload-issue/ Share on other sites More sharing options...
mrMarcus Posted December 8, 2009 Share Posted December 8, 2009 can you show us config.php? would really help in finding a possible issue if we had the code Link to comment https://forums.phpfreaks.com/topic/184433-image-text-upload-issue/#findComment-973644 Share on other sites More sharing options...
Wayniac Posted December 8, 2009 Author Share Posted December 8, 2009 Thank you for your reply, here you go <?php $dbhost="localhost"; #SQL Database Hostname $dbusername="root"; #SQL Username $dbpassword=""; #SQL Password $dbname="album"; #SQL Database Name // Connect to Mysql $connect = mysql_connect($dbhost, $dbusername, $dbpassword); //Select the correct database. $db = mysql_select_db($dbname,$connect) or die ("Could not select database"); ?> Link to comment https://forums.phpfreaks.com/topic/184433-image-text-upload-issue/#findComment-973653 Share on other sites More sharing options...
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