devang23 Posted December 9, 2009 Share Posted December 9, 2009 i have this script and everytime i load it to see the information that was entered into the first name part doesnt show up, and it says )able at the top. <html><head><title>I'm a GENUIS</title></head> <body> <?php $conn=mysql_connect("mysql4.000webhost.com","a3213677_dolphin","hello23") or die(mysql_error()); $rs = mysql_select_db("a3213677_snorre", $conn) or die("NOOOPE"); $sql="select * from `User Table` Where 1"; $rs=mysql_query($sql,$conn) or die(mysql_error());; $list = "<table border=\"1\" cellpadding=\"2\">"; $list.="<tr><th><First Name</th>"; $list.="<th>Last Name</th>"; $list.="<th>UserName</th>"; $list.="<th>PassWord</th></tr>"; while($row= mysql_fetch_array($rs) ) { $list .= "<tr>"; $list .= "<td>".$row["first_name"]."</td>"; $list .= "<td>".$row["last_name"]."</td>"; $list .= "<td>".$row["username"]."</td>"; $list .= "<td>".$row["password"]."</td>"; $list .= "</tr>"; } $list .= "<\table"; echo($list); ?> </body><html> Quote Link to comment Share on other sites More sharing options...
sasa Posted December 9, 2009 Share Posted December 9, 2009 move username and password from your post try <?php $conn=mysql_connect("********","*******","*******") or die(mysql_error()); $rs = mysql_select_db("*******", $conn) or die("NOOOPE"); $sql="select * from `User Table` Where 1"; $rs=mysql_query($sql,$conn) or die(mysql_error());; $row= mysql_fetch_array($rs) ) print_r($row); ?> and post output Quote Link to comment Share on other sites More sharing options...
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