phpfan101 Posted December 9, 2009 Share Posted December 9, 2009 So, on my website, i have added a "last active" feature, so if someone is surfing the site, they can view when another users last page visit was. so, every second, +1 is added to the $ts variable what i have now, working and all, shows ONLY "NOW!", or ONLY "1 second", ONLY "___ seconds ago"... and so on I have tred over, and over, and over to fix this to my liking, with more instances available, as an example, my current script will show somebody who is 13 months and 26 days inactive, just as "1 year", i want to see the "1 year, 1 month, and 26 days inactive"... or even simpler, just so it displays days/minutes/seconds/NOW! function howlongtil($ts) { $ts=$ts - time(); if ($ts<1) // <1 second return " NOW"; elseif ($ts==1) // <1 second return $ts." second"; elseif ($ts<60) // <1 minute return $ts." seconds"; elseif ($ts<120) // 1 minute return "1 minute"; elseif ($ts<60*60) // <1 hour return floor($ts/60)." minutes"; elseif ($ts<60*60*2) // <2 hour return "1 hour"; elseif ($ts<60*60*24) // <24 hours = 1 day return floor($ts/(60*60))." hours"; elseif ($ts<60*60*24*2) // <2 days return "1 day"; elseif ($ts<(60*60*24*7)) // <7 days = 1 week return floor($ts/(60*60*24))." days"; elseif ($ts<60*60*24*30.5) // <30.5 days ~ 1 month return floor($ts/(60*60*24*7))." weeks"; elseif ($ts<60*60*24*365) // <365 days = 1 year return floor($ts/(60*60*24*30.5))." months"; else // more than 1 year return floor($ts/(60*60*24*365))." years"; }; anyone know how? Link to comment https://forums.phpfreaks.com/topic/184570-activity-stump/ Share on other sites More sharing options...
phpfan101 Posted December 12, 2009 Author Share Posted December 12, 2009 Bump (still no luck) Link to comment https://forums.phpfreaks.com/topic/184570-activity-stump/#findComment-976241 Share on other sites More sharing options...
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