says permission denied at "xmlhttp.open("GET",url,true);" line

[lokesh_kumar_s]

function LookUp()

{

xmlhttp=GetXmlHttpObject();

if (xmlhttp==null)

  {

  alert ("Your browser does not support XMLHTTP!");

  return;

  }

//1st see if symbol entered by user is not null

var symbol=document.getElementById('Symbol').value;

if(symbol.length!=0)

{

 

var url="http://d.yimg.com/autoc.finance.yahoo.com/autoc/autoc?query="+symbol+"&callback=YAHOO.util.ScriptNodeDataSource.callbacks";

 

 

 

xmlhttp.onreadystatechange=LookUpstateChanged;

 

xmlhttp.open("GET",url,true);

 

xmlhttp.send(null);

}

 

}

i written the following method. but showing as  permission denied at "xmlhttp.open("GET",url,true);" line.

please see file i am attaching

 

[attachment deleted by admin]

[rajivgonsalves]

you cannot make a call to a website of another domain due to security constraints you will have to build a php file on your server to process the request