Preserving Original links in an array?

[Modernvox]

Happy New Year Guyz Hope everyone made it out okay

 

I have this code which returns CL Postings pertaining to Musicians. The only problems I see are:

 

1. It shows array[0] being the data i need, but in the script it shows array/Post[1] being printed which is confusing me?

Is it Array[0] or Array[1] being displayed first in the script?

Also, I need the link to remain intact, that is, linking back to CL.

 

So here's what the output is that I need which are actually links: However I DO NOT want the Array syntax included i.e. [0] =>, [1] =>  etc..

           

            [0] => Female Singer needed - (providence)

            [1] => JANUARY 8th, FRIDAY NIGHT - ROCK / PUNK / PSYCHOBILLY - (New Bedford)

            [2] => Looking for a musician who is very open minded?.. - (New Bedford / Rochester)

            [3] => DRUMMER/VOCALS - (SE MASS)

            [4] => Gig for gig... - (Boston)

            [5] => BASS AVAILABLE For Bluesy,Rootsy,Classic,Hard Rock. - (Cape / Boston / RI)

            [6] => Songwriters ????? - (south coast)

            [7] => New Years Eve Party - (Belmont Club Fall River)

            [8] => we need a frontman and bassist - (new bedford ma)

            [9] => LOOKING FOR BASS PLAYER - (Taunton, MA)

            [10] => Band Ready to Gig Seeks Bassist - (Southcoast,MA)

            [11] => Progressive Psychedelic Rock Band Auditioning Drummers - (Plymouth)

            [12] => DRUM  LESSONS>>>>>>>with Mike Levesque - (S.E. MA)

            [13] => 4 BAD MOTHERFUCKER shows this wek - (new bedford)

            [14] => Singing in the bedroom..."Start" the Jam - (Stuck in the 80's)

 

Here is my code:

<?php
$html = file_get_contents("http://southcoast.craigslist.org/muc/");

preg_match_all('/<a href="([^"]+)">([^<]+)<\/a><font size="-1">([^"]+)<\/font>/s', $html,$posts);
echo "<pre>";print_r($posts);
foreach ($posts as $post)
{
    print $post[1];
   

}
?> 

 

 

Any help greatly appreciated.

[MadTechie]

You probably want the Set Order

for example

<?php
$html = file_get_contents("http://southcoast.craigslist.org/muc/");

preg_match_all('/<a href="([^"]+)">([^<]+)<\/a><font size="-1">([^"]+)<\/font>/s', $html,$posts,PREG_SET_ORDER);
//echo "<pre>";print_r($posts);
foreach ($posts as $post)
{
    //print $post[0]; //HTML
    print $post[1]; //Link
    print $post[2]; //Description
    print $post[3]; //Short Text
   
    print "<BR />\n";
}
?> 

[Modernvox]

You probably want the Set Order

for example

<?php
$html = file_get_contents("http://southcoast.craigslist.org/muc/");

preg_match_all('/<a href="([^"]+)">([^<]+)<\/a><font size="-1">([^"]+)<\/font>/s', $html,$posts,PREG_SET_ORDER);
//echo "<pre>";print_r($posts);
foreach ($posts as $post)
{
    //print $post[0]; //HTML
    print $post[1]; //Link
    print $post[2]; //Description
    print $post[3]; //Short Text
   
    print "<BR />\n";
}
?> 

 

Displays the data, but without working link displays as:

/muc/1534468295.htmlLookin for a rockin singer for working band - (SE Mass)

/muc/1533839037.htmlFemale Singer needed - (providence)

/muc/1533816253.htmlJANUARY 8th, FRIDAY NIGHT - ROCK / PUNK / PSYCHOBILLY - (New Bedford)

 

Notice the muc/1534468295.html in front? This shouldn't be showing there..

[MadTechie]

Well it was an example for the order of the array!,

format the text however you wish, hence the comments stating whats what, or just use the HTML line (i commented it out for ease of use)

 

[Modernvox]

Well it was an example for the order of the array!,

format the text however you wish, hence the comments stating whats what, or just use the HTML line (i commented it out for ease of use)

 

Understood MT , I have the text/data in check , but why can't I get the link to be active? It just keeps pointing to localhost or wherever else I run the script. I want it to open in it's original location which is craigslist

[MadTechie]

if you have a link without the domain at the start it will append to the current domain,

so for example

<a href="/login.php">login</a> 

will go to the login.php of the current domain (here would be http://www.phpfreaks.com/login.php, on google.com it would be google.com/login.php etc etc

 

this might work (may need some tweaking)

<?php
$url = "http://southcoast.craigslist.org";
$html = file_get_contents("$url/muc/");

preg_match_all('/<a href="([^"]+)">([^<]+)<\/a><font size="-1">([^"]+)<\/font>/s', $html,$posts,PREG_SET_ORDER);
//echo "<pre>";print_r($posts);
foreach ($posts as $post)
{
    //print $post[0]; //HTML
    $post[2] = str_ireplace($url,"",$post[2]); //remove domain
    echo "<a href=\"$url/{$post[1]}\">{$post[2]}<\/a><font size=\"-1\">{$post[3]}<\/font>";
    print "<BR />\n";
}
?> 

[Modernvox]

if you have a link without the domain at the start it will append to the current domain,

so for example

<a href="/login.php">login</a> 

will go to the login.php of the current domain (here would be http://www.phpfreaks.com/login.php, on google.com it would be google.com/login.php etc etc

 

this might work (may need some tweaking)

<?php
$url = "http://southcoast.craigslist.org";
$html = file_get_contents("$url/muc/");

preg_match_all('/<a href="([^"]+)">([^<]+)<\/a><font size="-1">([^"]+)<\/font>/s', $html,$posts,PREG_SET_ORDER);
//echo "<pre>";print_r($posts);
foreach ($posts as $post)
{
    //print $post[0]; //HTML
    $post[2] = str_ireplace($url,"",$post[2]); //remove domain
    echo "<a href=\"$url/{$post[1]}\">{$post[2]}<\/a><font size=\"-1\">{$post[3]}<\/font>";
    print "<BR />\n";
}
?> 

 

Yep, Took out the extra / after echo "<a href=\"$url/{$post[1]}\and it works as expected. Thank You