echo <<<HTML | PLEASE HEEELPPPPP

farnoise · January 19, 2010

Good day,

I'm having this code here, its a HTML table that is showing up in my PHP page everything works fine but the problem is, It doesn't show any data in the echo section.

PS: There is nothing wrong with my connection string or other stuff, because if I call the variables outside of this table I can see them but I cant see anything inside the table. Should I use any variable encoder or something???????

please HELP

>>>>>>>>>PHP CODES<<<<<<<<<<<<<<

mysql_connect("localhost", "admin", "Pass") or die(mysql_error()); 
mysql_select_db("movedb") or die(mysql_error()); 

$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find); 

$data = mysql_query("SELECT * FROM sheet1sa WHERE upper($field) LIKE'%$find%'"); 

while($result = mysql_fetch_array( $data )) 
{ 

echo <<<HTML
<table width="400" border="0" class="sample">
  <tr>
    <td width="97" rowspan="5"><? echo $F6; ?> </td>
    <td width="125">Name, Lastname</td>
    <td width="164"> <? echo $name; ?> </td>
  </tr>
  <tr>
    <td>Cell Number </td>
    <td> <?php echo $cell; ?> </td>
  </tr>
  <tr>
    <td>Extension Number </td>
    <td> <?php echo $ext; ?> </td>
  </tr>
  <tr>
    <td>Office Number </td>
    <td><?php echo $F2; ?> </td>
  </tr>
  <tr>
    <td>Department</td>
    <td><?php echo $dep; ?> </td>
  </tr>
</table>
<br>
<br>

HTML;


}

>>>>>>>>>PHP CODES<<<<<<<<<<<<<<

taquitosensei · January 19, 2010

I don't think it will parse the php that way. Try this

>>>>>>>>>PHP CODES<<<<<<<<<<<<<<

mysql_connect("localhost", "admin", "Pass") or die(mysql_error());
mysql_select_db("movedb") or die(mysql_error());

$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);

$data = mysql_query("SELECT * FROM sheet1sa WHERE upper($field) LIKE'%$find%'");

while($result = mysql_fetch_array( $data ))
{ 
// 
?> 
<table width="400" border="0" class="sample">
  <tr>
    <td width="97" rowspan="5"><?php echo $F6; ?></td>
    <td width="125">Name, Lastname</td>
    <td width="164"><?php echo $name; ?></td>
  </tr>
  <tr>
    <td>Cell Number </td>
    <td><?php echo $cell; ?></td>
  </tr>
  <tr>
    <td>Extension Number </td>
    <td><?php echo $ext; ?></td>
  </tr>
  <tr>
    <td>Office Number </td>
    <td><?php $F2; ?></td>
  </tr>
  <tr>
    <td>Department</td>
    <td><?php echo $dep; ?></td>
  </tr>
</table>
<br>
<br>
<?php 
}

Buddski · January 19, 2010

If you were to replace your, <?php echo $dep; ?> with {$dep}, for example, it will work inside your heredoc statement..

farnoise · January 19, 2010

?>
<table width="400" border="0" class="sample">  <tr>    
<td width="97" rowspan="5"><?php echo $F6; ?></td>    
<td width="125">Name, Lastname</td>    <td width="164">{$name}, </td>  </tr>  
<tr>    <td>Cell Number </td>    <td><?php echo {$cell},  ?></td>  </tr>  
<tr>    <td>Extension Number </td>    <td><?php echo $ext; ?></td>  </tr>  
<tr>    <td>Office Number </td>    <td><?php $F2; ?></td>  </tr>  
<tr>    <td>Department</td>    <td><?php echo $dep; ?></td>  </tr></table><br>
<br>
<?php

Neither of these works !!!!

Well the last reply messed up my pgae

Buddski · January 19, 2010

You arent actually defining those values, as far as I can tell anyway.

You need to either define them or replace them with $result['field_name']

farnoise · January 19, 2010

Bu as I said if I just call this variabales ouside of my HTML area I can see the result so there is nothing wrong with that variable example if i use


$data = mysql_query("SELECT * FROM sheet1sa WHERE upper($field) LIKE'%$find%'"); 
while($result = mysql_fetch_array( $data )) 
{ 

echo $cell;

I'll see the cell number but if I put in that HTML format nothing shows up

Buddski · January 19, 2010

Are you getting the HTML output at all? or are the vars just not showing up..

farnoise · January 19, 2010

Yes im getting My Table every thing works just fine, But I dont see VARs!!

Just want to remember again: If I use my echo command outside my HTML section I can see the VARS so it means everything is ok in PHP

Buddski · January 19, 2010

You may be getting some errors..

error_reporting(E_ALL);
ini_set('display_errors',1);

farnoise · January 19, 2010

I'm pretty sure there is no error, I've tried that I didnt get anything..

well here is my whole scrpt do you mind take a look at it and tell me if it looks OK or not!?

<link href="../css/lightstyle.css" type="text/css" rel="stylesheet" />
<?php include("../header.php"); ?>
<script type="text/JavaScript">
<!--
function MM_jumpMenu(targ,selObj,restore){ //v3.0
  eval(targ+".location='"+selObj.options[selObj.selectedIndex].value+"'");
  if (restore) selObj.selectedIndex=0;
}
//-->
</script>

<form name="search" method="post" action="<?=$PHP_SELF?>">
<fieldset><legend>Phonebook System</legend><input name="find" type="text" value="Search" maxlength="100" />
  <div align="left"><h5>
    
    <Select NAME="field" class="arad">
      <option value="name">Name and(or) Last name</option>
      <option value="cell">Cell Number</option>
      <option value="ext">Extension / Office</option>
      <option value="dep">Department</option>
    </Select>
    <input type="hidden" name="searching" value="yes" />
    <input type="submit" name="search" value="Search" class="btt1"/>
  </div>
</form>

  
    <div align="left">
      <p>
        <? 
if ($searching =="yes") 
{ 
echo "<h5>Results<p>"; 

if ($find == "") 
{ 
echo "<p>You forgot to enter a search criteria"; 
exit; 
} 

mysql_connect("localhost", "Uganda", "u^77HYuj***$$") or die(mysql_error()); 
mysql_select_db("movedb") or die(mysql_error()); 


$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find); 

//Now we search for our search term, in the field the user specified 
$data = mysql_query("SELECT * FROM sheet1sa WHERE upper($field) LIKE'%$find%'"); 

while($result = mysql_fetch_array( $data )) 
{ 

echo <<<HTML
<table width="400" border="0" class="sample">
  <tr>
    <td width="97" rowspan="5"><? echo $F6; ?> </td>
    <td width="125">Name, Lastname</td>
    <td width="164"> <? echo $name; ?> </td>
  </tr>
  <tr>
    <td>Cell Number </td>
    <td> <?php echo $cell; ?> </td>
  </tr>
  <tr>
    <td>Extension Number </td>
    <td> <?php echo $ext; ?> </td>
  </tr>
  <tr>
    <td>Office Number </td>
    <td><?php echo $F2; ?> </td>
  </tr>
  <tr>
    <td>Department</td>
    <td><?php echo $code; ?> </td>
  </tr>
</table>
<br>
<br>

HTML;


} 
$anymatches=mysql_num_rows($data); 
if ($anymatches == 0) 
{ 
echo "<h5>Sorry, but I can not find the person that you are looking for.<br>Please .<br><br>Thanks"; 
} 

//And we remind them what they searched for 
echo "<b><h5>Searched For:</b></b> " .$find; 
echo "<br>"; 
echo "<br>"; 
} 
?>
<head>
</head>
<body>
      </p>
      <p> </p>
      <hr width="500" size="1" />
      <p> </p>
      <p> </p>
      <p align="center">
</p>
</body>
  </html>

Buddski · January 19, 2010

Apart from your HTML being all messed up

<head>
</head>
<body>

at the bottom of the page.. I still cannot see where you are defining those variables you are trying to call..

You also cannot use <?php ?> inside a HEREDOC statement..

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