senyo Posted January 21, 2010 Share Posted January 21, 2010 I found a good script that uploads an image but but I want to integrate it in another script and I can't do it because it has two files and it needs a user to make it wok, the first sends the image to the second that uploads and renames the image but even if they are joined the page is reloaded. I want to make them work as one, to take image from a variable, upload the image to the remote server and return the image address. The form <?php // filename: upload.form.php // first let's set some variables // make a note of the current working directory relative to root. $directory_self = str_replace(basename($_SERVER['PHP_SELF']), '', $_SERVER['PHP_SELF']); // make a note of the location of the upload handler $uploadHandler = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'upload.processor.php'; // set a max file size for the html upload form $max_file_size = 200000; // size in bytes // now echo the html page ?> <head><meta http-equiv="content-type" content="text/html; charset=iso-8859-1"> <link rel="stylesheet" type="text/css" href="stylesheet.css"> <title>Upload form</title></head> <body> <form id="Upload" action="<?php echo $uploadHandler ?>" enctype="multipart/form-data" method="post"> <h1>Upload form</h1> <p><input type="hidden" name="MAX_FILE_SIZE" value="<?php echo $max_file_size ?>"> </p><p><label for="file">File to upload:</label><input id="file" type="file" name="file"> </p><p><label for="submit">Press to...</label> <input id="submit" type="submit" name="submit" value="Upload me!"></p></form> </body></html> The uploader <?php // filename: upload.processor.php // first let's set some variables // make a note of the current working directory, relative to root. $directory_self = str_replace(basename($_SERVER['PHP_SELF']), '', $_SERVER['PHP_SELF']); // make a note of the directory that will recieve the uploaded files $uploadsDirectory = $_SERVER['DOCUMENT_ROOT'] . $directory_self . 'uploaded_files/'; // make a note of the location of the upload form in case we need it $uploadForm = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'upload.form.php'; // make a note of the location of the success page $uploadSuccess = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'upload.success.php'; // name of the fieldname used for the file in the HTML form $fieldname = 'file'; // Now let's deal with the upload // possible PHP upload errors $errors = array(1 => 'php.ini max file size exceeded', 2 => 'html form max file size exceeded', 3 => 'file upload was only partial', 4 => 'no file was attached'); // check the upload form was actually submitted else print form isset($_POST['submit']) or error('the upload form is neaded', $uploadForm); // check for standard uploading errors ($_FILES[$fieldname]['error'] == 0) or error($errors[$_FILES[$fieldname]['error']], $uploadForm); // check that the file we are working on really was an HTTP upload @is_uploaded_file($_FILES[$fieldname]['tmp_name']) or error('not an HTTP upload', $uploadForm); // validation... since this is an image upload script we // should run a check to make sure the upload is an image @getimagesize($_FILES[$fieldname]['tmp_name']) or error('only image uploads are allowed', $uploadForm); // make a unique filename for the uploaded file and check it is // not taken... if it is keep trying until we find a vacant one $now = time(); while(file_exists($uploadFilename = $uploadsDirectory.$now.'-'.$_FILES[$fieldname]['name'])) { $now++; } // now let's move the file to its final and allocate it with the new filename @move_uploaded_file($_FILES[$fieldname]['tmp_name'], $uploadFilename) or error('receiving directory insuffiecient permission', $uploadForm); // If you got this far, everything has worked and the file has been successfully saved. // We are now going to redirect the client to the success page. echo 'Image address<br>'; echo $uploadFilename; //header('Location: ' . $uploadSuccess); // make an error handler which will be used if the upload fails function error($error, $location, $seconds = 10) { header("Refresh: $seconds; URL=\"$location\""); echo '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"'."\n". '"http://www.w3.org/TR/html4/strict.dtd">'."\n\n". '<html lang="en">'."\n". ' <head>'."\n". ' <meta http-equiv="content-type" content="text/html; charset=iso-8859-1">'."\n\n". ' <link rel="stylesheet" type="text/css" href="stylesheet.css">'."\n\n". ' <title>Upload error</title>'."\n\n". ' </head>'."\n\n". ' <body>'."\n\n". ' <div id="Upload">'."\n\n". <h1>Upload failure</h1>'."\n\n". ' <p>An error has occured: '."\n\n". ' <span class="red">' . $error . '...</span>'."\n\n". ' The upload form is reloading</p>'."\n\n". ' </div>'."\n\n". '</html>'; exit; } // end error handler ?> Link to comment https://forums.phpfreaks.com/topic/189344-upload-image-to-remote-server-from-localhost/ Share on other sites More sharing options...
senyo Posted January 21, 2010 Author Share Posted January 21, 2010 The main problem is how the form is sending the image I think that you can upload without reloading the page with functions. But I don't know how to send the images to the upload.processor because I don't know how the form sends the file <form id="Upload" action="<?php echo $uploadHandler ?>" enctype="multipart/form-data" method="post"> <label for="file">File to upload:</label><input id="file" type="file" name="file"> Link to comment https://forums.phpfreaks.com/topic/189344-upload-image-to-remote-server-from-localhost/#findComment-999564 Share on other sites More sharing options...
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