why wont this echo?

[seany123]

As i said,

You didn't pass anything in the URL.. add ?ref=10 to it!

 

for that form to process you need to POST the form BUT the form is NOT passing the get

<form method="POST" action="register.php">

 

for example try

<form method="POST" action="register.php?ref=10">

 

ooh i see BUT the problem is i want to allow my players to use it as a Refferal link... so they can type ref= whatever they id is.

 

[MadTechie]

Okay, change it to a POST and add the input to the form (could be hidden)

ie

<INPUT type="hidden" value="<?php $_GET['ref']?>">

OR leave as GET

<form method="POST" action="register.php?ref=<?php $_GET['ref']?>">

(personally i'll use the hidden field)

 

other options are sessions, cookies

[seany123]

okay so what i have done is this added this just below the

<form method='POST' action='register.php'>

 

i added this:

 

<input type="hidden" value="<?php $_GET['ref']?>" name="refid">

 

then where the query is i added:

 

	if($_POST['ref'] >= 1)
	{
	$ref_id = $_POST['refid'];
	$insert['ref'] = $ref_id;
	}

 

now that should work right?

 

EDIT: it didnt work

[MadTechie]

Not quite

if($_POST['ref'] >= 1)

should be

if($_POST['refid'] >= 1)

[seany123]

Not quite

if($_POST['ref'] >= 1)

should be

if($_POST['refid'] >= 1)

 

that still hasn't worked omg lol

 

	if($_POST['refid'] >= 1)
	{
	$ref_id = $_POST['refid'];
	$insert['ref'] = $ref_id;
	}
	echo $insert['ref'];

 

also $insert['ref'] isnt echoing.

[MadTechie]

change

<input type="hidden" value="<?php $_GET['ref']?>" name="refid">

to

<input type="text" value="<?php $_GET['ref']?>" name="refid">

and check the value is in their

if it is then do a

print_r($_POST);

[seany123]

its not there!

 

thats weird i now changed it to:

 

<input type="text" value="<?=$_GET['ref'];?>" name="refid">

 

and it appears

 

but surely short tags are not the way forward lol!